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vlk dot charles at gmail dot com
1 year ago
I think it is worth mentioning that the array passed as the first argument is not modified and is left intact. A new array is returned. I think the wording of this documentation could be improved because it suggests that the passed array *is* modified.

If you want to modify your existing array, it is not enough to do:

array_replace($arrayToModify, $arrayWithModifications);

You have to assign the returned value back to it like so:

$arrayToModify = array_replace($arrayToModify, $arrayWithModifications);

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