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raat1979 at gmail dot com
9 years ago
Unfortunately array_push returns the new number of items in the array
It does not give you the key of the item you just added, in numeric arrays you could do -1, you do however need to be sure that no associative key exists as that would break the assumption

It would have been better if array_push would have returned the key of the item just added like the below function
(perhaps a native variant would be a good idea...)

<?php

if(!function_exists('array_add')){
function
array_add(array &$array,$value /*[, $...]*/){
$values = func_get_args(); //get all values
$values[0]= &$array; //REFERENCE!
$org=key($array); //where are we?
call_user_func_array('array_push',$values);
end($array); // move to the last item
$key = key($array); //get the key of the last item
if($org===null){
//was at eof, added something, move to it
return $key;
}elseif(
$org<(count($array)/2)){ //somewhere in the middle +/- is fine
reset($array);
while (
key($array) !== $org) next($List);
}else{
while (
key($array) !== $org) prev($List);
}
return
$key;
}
}
echo
"<pre>\n";
$pr = array('foo'=>'bar','bar'=>'foo');
echo
"Taken array;";
print_r($pr);

echo
"\npush 1 returns ".array_push($pr,1)."\n";
echo
"------------------------------------\n";
$pr = array('foo'=>'bar','bar'=>'foo');
echo
"\npush 2 returns ".array_push($pr,1,2)."\n";
echo
"------------------------------------\n";
$pr = array('foo'=>'bar','bar'=>'foo');
echo
"\n add 1 returns ".array_add($pr,2)."\n\n";
echo
"------------------------------------\n";
$pr = array('foo'=>'bar','bar'=>'foo');
echo
"\n add 2 returns ".array_add($pr,1,2)."\n\n";
echo
"<pre/>\n\n";
?>
Outputs:
Taken array;Array
(
[foo] => bar
[bar] => foo
)

push 1 returns 3
------------------------------------

push 2 returns 4
------------------------------------

add 1 returns 0

------------------------------------

add 2 returns 1

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