// C program for the above approach
#include <inttypes.h>
#include <stdio.h>
#include <stdlib.h>
// Structure of a node
// of XOR Linked List
struct Node {
// Stores data value
// of a node
int data;
// Stores XOR of previous
// pointer and next pointer
struct Node* nxp;
};
// Function to calculate
// Bitwise XOR of the two nodes
struct Node* XOR(struct Node* a,
struct Node* b)
{
return (struct Node*)((uintptr_t)(a)
^ (uintptr_t)(b));
}
// Function to insert a node with
// given value at given position
struct Node* insert(struct Node** head,
int value)
{
// If XOR linked list is empty
if (*head == NULL) {
// Initialize a new Node
struct Node* node
= (struct Node*)malloc(
sizeof(struct Node));
// Stores data value in the node
node->data = value;
// Stores XOR of previous
// and next pointer
node->nxp = XOR(NULL, NULL);
// Update pointer of head node
*head = node;
}
// If the XOR linked
// list is not empty
else {
// Stores the address
// of the current node
struct Node* curr = *head;
// Stores the address
// of the previous node
struct Node* prev = NULL;
// Initialize a new Node
struct Node* node
= (struct Node*)malloc(
sizeof(struct Node));
// Update address of current node
curr->nxp = XOR(node,
XOR(
NULL, curr->nxp));
// Update address of the new node
node->nxp = XOR(NULL, curr);
// Update the head node
*head = node;
// Update the data
// value of current node
node->data = value;
}
return *head;
}
// Function to print elements
// of the XOR Linked List
void printList(struct Node** head)
{
// Stores XOR pointer
// in the current node
struct Node* curr = *head;
// Stores XOR pointer
// in the previous Node
struct Node* prev = NULL;
// Stores XOR pointer in the
// next node
struct Node* next;
// Traverse XOR linked list
while (curr != NULL) {
// Print the current node
printf("%d ", curr->data);
// Forward traversal
next = XOR(prev, curr->nxp);
// Update the prev pointer
prev = curr;
// Update the curr pointer
curr = next;
}
}
// Function to reverse the linked
// list in the groups of K
struct Node* reverseK(struct Node** head,
int K, int len)
{
struct Node* curr = *head;
// If head is NULL
if (curr == NULL)
return NULL;
// If the size of XOR linked
// list is less than K
else if (len < K)
return *head;
else {
int count = 0;
// Stores the XOR pointer
// in the previous Node
struct Node* prev = NULL;
// Stores the XOR pointer
// in the next node
struct Node* next;
while (count < K) {
// Forward traversal
next = XOR(prev, curr->nxp);
// Update the prev pointer
prev = curr;
// Update the curr pointer
curr = next;
// Count the number of
// nodes processed
count++;
}
// Remove the prev node
// from the next node
prev->nxp = XOR(NULL,
XOR(prev->nxp,
curr));
// Add the head pointer with prev
(*head)->nxp = XOR(XOR(NULL,
(*head)->nxp),
curr);
// Add the prev with the head
if (curr != NULL)
curr->nxp = XOR(XOR(curr->nxp,
prev),
*head);
return prev;
}
}
// Function to reverse last K nodes
// of the given XOR Linked List
void reverseLL(struct Node* head,
int N, int K)
{
// Reverse the given XOR LL
head = reverseK(&head, N, N);
// Reverse the first K nodes of
// the XOR LL
head = reverseK(&head, K, N);
// Reverse the given XOR LL
head = reverseK(&head, N, N);
// Print the final linked list
printList(&head);
}
// Driver Code
int main()
{
// Stores number of nodes
int N = 6;
// Given XOR Linked List
struct Node* head = NULL;
insert(&head, 1);
insert(&head, 3);
insert(&head, 11);
insert(&head, 8);
insert(&head, 6);
insert(&head, 7);
int K = 3;
reverseLL(head, N, K);
return (0);
}