wxPython - IsEnabled() function in wx.MenuItem

wxPython – IsSubMenu() function in wx.MenuItem

Last Updated : 09 Jun, 2020

In this article we are going to learn about IsSubMenu() function associated with wx.MenuItem class of wxPython. IsSubMenu() function simply returns True if the item is a submenu and False if the item is not a submenu.
No parameters are required by IsSubMenu() function.

Syntax:

wx.MenuItem.IsSubMenu(self)

Parameters:

No parameters are required by IsSubMenu() function.

Return Type:

bool

Code Example:

import wx 
  
  
class Example(wx.Frame): 
  
    def __init__(self, *args, **kwargs): 
        super(Example, self).__init__(*args, **kwargs) 
  
        self.InitUI() 
  
    def InitUI(self): 
  
        menubar = wx.MenuBar() 
  
        fileMenu = wx.Menu() 
  
        sm = wx.Menu() 
        sm.Append(wx.ID_ANY, 'Submenu item 1') 
        sm.Append(wx.ID_ANY, 'Submenu item 2') 
        sm.Append(wx.ID_ANY, 'Submenu item 3') 
        item = wx.MenuItem(fileMenu, 1, '&Check\tCtrl + c', helpString ="Check Help") 
        item.SetSubMenu(sm) 
        fileMenu.AppendMenu(wx.ID_ANY, 'I&mport', sm) 
          
        n = item.IsSubMenu() 
        # if item is sub menu 
        if(n == True): 
            print("Item is SubMenu Item") 
        else: 
            print("Item is not a SubMenu Item") 
        menubar.Append(fileMenu, '&File') 
        self.SetMenuBar(menubar) 
  
        self.SetSize((350, 250)) 
        self.SetTitle('Submenu') 
        self.Centre() 
  
  
  
  
def main(): 
  
    app = wx.App() 
    ex = Example(None) 
    ex.Show() 
    app.MainLoop() 
  
  
if __name__ == '__main__': 
    main() 

Output:

Item is SubMenu Item.

Output Window:

wxPython - IsEnabled() function in wx.MenuItem

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RahulSabharwal

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Practice Tags :

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