Open In App

URL toURI() method in Java with Examples

Last Updated : 07 Nov, 2019
Comments
Improve
Suggest changes
Like Article
Like
Report
The getURI() function of URL class converts the URL object to a URI object. Any URL which compiles with RFC 2396 can be converted to URI. URLs which are not in the specified format will generate an error if converted to URI format. Function Signature
public URI toURI()
Syntax
url.toURI()
Parameter: This method do not accept any parameter. Return type: This function returns a URI object which is converted from this URL object. Exception: This function throws URISyntaxException if this URL is not formatted strictly according to RFC2396 and cannot be converted to a URI. Below examples will illustrate the use of toURI() function: Example 1: Java
// Java program to convert URL to URI

import java.net.*;

class GFG {
    public static void main(String args[])
    {

        // url and uri objects
        URL url = null;
        URI uri = null;

        try {

            // create a URL
            url = new URL("https://www.geeksforgeeks.org");

            // display the URL
            System.out.println("URL: " + url);

            // convert the URL to URI
            uri = url.toURI();

            // display the URI
            System.out.println("URI: " + uri);
        }
        // if any error occurs
        catch (Exception e) {

            // display the error
            System.out.println(e);
        }
    }
}
Output:
URL: https://www.geeksforgeeks.org
URI: https://www.geeksforgeeks.org
Example 2: Java
// Java program to convert URL to URI

import java.net.*;

class GFG {
    public static void main(String args[])
    {

        // url and uri objects
        URL url = null;
        URI uri = null;

        try {

            // create an invalid URL
            url = new URL("https://www.geeksfor>geeks.com");

            // display the URL
            System.out.println("URL: " + url);

            // convert the URL to URI
            uri = url.toURI();

            // display the URI
            System.out.println("URI: " + uri);
        }
        // if any error occurs
        catch (Exception e) {

            // display the error
            System.out.println(e);
        }
    }
}
Output:
URL: https:// www.geeksfor>geeks.com
java.net.URISyntaxException:
 Illegal character in authority at index 8:
 https:// www.geeksfor>geeks.com

Next Article
Practice Tags :

Similar Reads