Tips and Tricks to Logarithm Question
Last Updated :
11 Nov, 2024
Logarithms are a crucial topic to master for the Quantitative Aptitude section of competitive exams, which requires not only understanding but also speed and accuracy.
This article provides essential tips and tricks for tackling logarithm questions effectively, covering key concepts, formulas, and rules that every learner should grasp before diving into practice.
Types of Logarithms
There are two main types of logarithms you’ll encounter: common logs and natural logs.
- Common Logarithm: Written as log (x), this log has a base of 10.
- It answers the question, “To what power must 10 be raised to equal x?”
- Common logs are often used in scales like pH, sound (decibels), and earthquake magnitudes.
- Example: log(100) = 2 (because 102 = 100).
- Natural Logarithm: Written as ln(x), this log has a base of e (approximately 2.718).
- It answers the question, “To what power must e be raised to equal x?”
- Natural logs are used in natural growth and decay models, like population growth and radioactive decay.
- Example: ln(e3) = 3.
Tips and Tricks for Logarithm
Below is a detailed table with Rules, equations, samples, and quick tricks to solve logarithm questions, remember the table below to quickly solve the questions.
Rule | Equation | Example | Quick Trick |
---|
Product Rule | logb(x ⋅ y) = logb(x) + logb(y) | log2(8⋅4) = log2(8) + log2(4) = 3 + 2 = 5 | Think "product" means "plus" |
---|
Quotient Rule | logb(x/y) = logb(x) − logb(y) | log3(27/3) = log3(27) − log3(3) = 3 − 1 = 2 | Think "quotient" means "minus" |
---|
Power Rule | logb(xk) = k⋅logb(x) | log2(43) = 3⋅log2(4) = 3⋅2 = 6 | Exponent becomes a "coefficient" |
---|
Change of Base Formula | logb(x) = logk(x)/logk(b) | log2(8) = log10(8)/log10(2) ≈ 3 | Use when the base needs to be changed |
---|
Zero Rule | logb(1) = 0 | log5(1) = 0 | A log of 1 is always 0 |
---|
Identity Rule | logb(b) = 1 | log7(7) = 1 | Base and number match = 1 |
---|
Inverse Rule | logb(bx) = x | log2(25) = 5 | Base matches inside power, use exponent |
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Negative Log Rule | logb(1/x) = −logb(x) | log2(1/4) = −2 | Flip fraction for a negative result |
---|
Common Logarithmic Values for Base 10 (log10) Table
Value | Approximate Logarithm log10 |
---|
log10(0) | Undefined |
---|
log10(1) | 0 |
---|
log10(2) | 0.301 |
---|
log10(3) | 0.477 |
---|
log10(4) | 0.602 |
---|
log10(5) | 0.699 |
---|
log10(6) | 0.778 |
---|
log10(7) | 0.845 |
---|
log10(8) | 0.903 |
---|
log10(9) | 0.954 |
---|
log10(10) | 1 |
---|
Tips for Solving Logarithmic Equations
Basic Logarithmic Equation
When you have a simple equation of the form logb(x) = y, you can rewrite it in its exponential form to solve for x: x = by
Example: Solve for x in log3(x) = 4.
Solution:
- Rewrite the equation in exponential form: x = 34
- Calculate 34: x = 81
So, x = 81
Equations with Logarithms on Both Sides
When you have an equation with logarithms on both sides and the same base, you can set the insides equal to each other.
Example: Solve for x in log4(x + 3) = log4(7)
Solution:
Set the insides equal to each other, since both sides have the same base (4), we can set the expressions inside the logarithms equal to each other:
so the value of x = 4.
Using Logarithmic Properties to Simplify
Sometimes, you’ll need to use logarithmic properties (product, quotient, or power rule) to simplify an equation before solving it.
Example: Solve for x in log2(4x) = 5
Solution:
- Use the product rule to separate the terms:
- Simplify log2(4) (since 22 = 4, so log2(4) = 2):
- Subtract 2 from both sides:
- Rewrite in exponential form: x = 23 = 8
So, x = 8.
Handling Logarithmic Equations with Different Bases
If you encounter logarithmic equations with different bases, use the change of base formula to convert one or both sides to a common base.
Example: Solve log2(x) = log3(9)
Solution:
- Convert log3(9), using change of base, the change of base formula states:
- log3(9) = log2(9)/log2(3)
- Substitute into the Equation:
- log2(x) = log2(9)/log2(3)
- Simplify the Right Side:
- Calculate log2(9) and log2(3) in terms of powers of 2:
- Since 9=32, we can use the power rule: log2(9) = log2(32) = 2⋅log2(3).
- Thus the equation becomes: log2(x) = 2⋅log2(3)/log2(3)
- Cancel log2(3) on the Right Side: log2(x) = 2
- Rewrite in Exponential Form
- Convert log2(x) = 2 to exponential form: x = 22 = 4
So, x = 4
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