sympy.stats.Weibull() in Python

sympy.stats.Zeta() in Python

Last Updated : 08 Jun, 2020

With the help of sympy.stats.Zeta() method, we can get the random variable representing the Zeta distribution.

Syntax : sympy.stats.Zeta(name, s)
Return : Return the random variable.

Example #1 :
In this example we can see that by using sympy.stats.Zeta() method, we are able to get the Zeta distribution by using this method.

# Import sympy and Zeta  
from sympy.stats import Zeta, density, E, variance 
from sympy import Symbol 
  
s = 7
  
# Using sympy.stats.Zeta() method 
X = Zeta("x", s) 
gfg = density(X)(0.33333) 
  
print(gfg) 

Output :

2187.15309612378/zeta(7)

Example #2 :

# Import sympy and Zeta  
from sympy.stats import Zeta, density, E, variance 
from sympy import Symbol 
  
s = 3
z = Symbol("z") 
  
# Using sympy.stats.Zeta() method 
X = Zeta("x", s) 
gfg = density(X)(z) 
  
print(gfg) 

Output :

1/(z**3*zeta(3))

sympy.stats.Weibull() in Python

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