SymPy | Polyhedron.faces() in Python

Last Updated : 27 Aug, 2019

Polyhedron.faces() : faces() is a sympy Python library function that returns the faces of the polyhedra.

Syntax : sympy.combinatorics.Polyhedrons.Polyhedron.faces() Return : faces of the Polyhedron.

Code #1 : faces() Example - tetrahedron

Python3 1=1

# Python code explaining
# SymPy.Polyhedron.faces()

# importing SymPy libraries
from sympy.combinatorics import Permutation, Cycle
from sympy.combinatorics.polyhedron import tetrahedron, octahedron

# Using from 
# sympy.combinatorics.polyhedron.Polyhedron.faces()

# Creating Polyhedron
a = tetrahedron.copy()

print ("Polyhedron - faces form : ", a.faces)

a.rotate(0)
print ("\nPolyhedron - faces form : ", a.faces)

Output :

Polyhedron - faces form : {(0, 1, 2), (0, 1, 3), (0, 2, 3), (1, 2, 3)} Polyhedron - faces form : {(0, 1, 2), (0, 1, 3), (0, 2, 3), (1, 2, 3)}

Code #2 : faces() Example - octahedron

Python3 1=1

# Python code explaining
# SymPy.Polyhedron.faces()

# importing SymPy libraries
from sympy.combinatorics import Permutation, Cycle
from sympy.combinatorics.polyhedron import tetrahedron, octahedron

# Using from 
# sympy.combinatorics.polyhedron.Polyhedron.faces()

# Creating Polyhedron
a = octahedron.copy()

print ("Polyhedron - faces form : ", a.faces)

a.rotate(0)
print ("\nPolyhedron - faces form : ", a.faces)

Output :

Polyhedron - faces form : {(0, 1, 2), (0, 1, 4), (0, 2, 3), (0, 3, 4), (1, 2, 5), (1, 4, 5), (2, 3, 5), (3, 4, 5)} Polyhedron - faces form : {(0, 1, 2), (0, 1, 4), (0, 2, 3), (0, 3, 4), (1, 2, 5), (1, 4, 5), (2, 3, 5), (3, 4, 5)}