Open In App

SOUNDS LIKE Function in MySQL

Last Updated : 14 Dec, 2020
Comments
Improve
Suggest changes
Like Article
Like
Report
SOUNDS LIKE : This function in MySQL is used to compare the Soundex codes of a given two string expressions. It is used as SOUNDEX(expr1) = SOUNDEX(expr2) to retrieve strings that sound similar. Syntax :
expr1 SOUNDS LIKE expr2
Parameter : It accepts two parameter as mentioned above and described below.
  • expr1 - The first string which we want to compare.
  • expr2 -The second string which we want to compare.
Returns : It compares the Soundex code of two string values and returns the output. Example-1 : Comparing similar two given string using SOUNDS LIKE Function.
SELECT 'geeks' SOUNDS LIKE 'geeks' 
as Result;
Output :
Result

    1

Example-2 : Comparing similar two given strings using SOUNDS LIKE Function.
SELECT 'geeks' SOUNDS LIKE 'for' 
as Result;
Output :
Result

    0

Example-3 : The following example shows returns all the rows which contain an Employee name whose first name sounds like 'Sayan'.
CREATE TABLE Employee
(
Employee_id INT AUTO_INCREMENT,  
First_name VARCHAR(100) NOT NULL,
Last_name VARCHAR(100) NOT NULL,
Joining_Date DATE NOT NULL,
PRIMARY KEY(Employee_id )
);
Inserting some data to the Employee table :
INSERT INTO Employee
(First_name ,Last_name , Joining_Date )
VALUES
('Sayantan', 'Majumdar', '2000-01-11'),
('Anushka', 'Samanta', '2002-11-10' ),
('Sayan', 'Sharma', '2005-06-11' ),
('Shayari', 'Das', '2008-01-21' ),
('Sayani', 'Jain', '2008-02-01' ),
('Tapan', 'Samanta', '2010-01-11' ),
('Deepak', 'Sharma', '2014-12-01'  ),
('Ankana', 'Jana', '2018-08-17'),
('Shreya', 'Ghosh', '2020-09-10') ;
So, the Employee Table is as follows.
select * from Employee ;
Output :
Employee_idFirst_nameLast_nameJoining_Date
1SayantanMajumdar2000-01-11
2AnushkaSamanta2002-11-10
3SayanSharma2005-06-11
4ShayariDas2008-01-21
5SayaniJain2008-02-01
6TapanSamanta2010-01-11
7DeepakSharma2014-12-01
8AnkanaJana2018-08-17
9ShreyaGhosh2020-09-10
Now, we are going to check those employee whose first name sounds like 'sayan'.
SELECT * FROM Employee 
WHERE First_name SOUNDS LIKE 'Sayan' ;
Output :
Employee_idFirst_nameLast_nameJoining_Date
3SayanSharma2005-06-11
5SayaniJain2008-02-01

Next Article
Article Tags :

Similar Reads