Skewed Binary Tree

Last Updated : 22 Jul, 2021

A skewed binary tree is a type of binary tree in which all the nodes have only either one child or no child.

Types of Skewed Binary trees

There are 2 special types of skewed tree:

1. Left Skewed Binary Tree:
These are those skewed binary trees in which all the nodes are having a left child or no child at all. It is a left side dominated tree. All the right children remain as null.

Below is an example of a left-skewed tree:

C++

#include <bits/stdc++.h>
using namespace std;

// A Tree node
struct Node {
    int key;
    struct Node *left, *right;
};

// Utility function to create a new node
Node* newNode(int key)
{
    Node* temp = new Node;
    temp->key = key;
    temp->left = temp->right = NULL;

    return (temp);
}

// Driver code
int main()
{
    /*
            1
           /
          2
         /
        3
    */
    Node* root = newNode(1);
    root->left = newNode(2);
    root->left->left = newNode(3);

    return 0;
}

Java

// Java implementation of above approach
import java.util.*;

class GFG
{
    
// A Tree node
static class Node 
{
    int key;
     Node left, right;
};
  
// Utility function to create a new node
static Node newNode(int key)
{
    Node temp = new Node();
    temp.key = key;
    temp.left = temp.right = null;
  
    return (temp);
}
  
// Driver code
public static void main(String args[])
{
    /*
            1
           /
          2
         /
        3
    */
    Node root = newNode(1);
    root.left = newNode(2);
    root.left.left = newNode(3);
}
}

// This code is contributed by Arnab Kundu

Python3

# Python3 implementation of the above approach 

# Class that represents an individual
# node in a Binary Tree 
class Node: 
    def __init__(self, key): 
        
        self.left = None
        self.right = None
        self.val = key 
        
# Driver code

"""         1
           /
          2
         /
        3     """
root = Node(1)
root.left = Node(2)
root.left.left = Node(2)

# This code is contributed by dhruvsantoshwar

// C# implementation of above approach 
using System;
 
class GFG 
{ 
         
    // A Tree node 
     public class Node 
    { 
         public int key; 
         public Node left, right; 
    }; 
         
    // Utility function to create a new node 
     static Node newNode(int key) 
    { 
        Node temp = new Node(); 
        temp.key = key; 
        temp.left = temp.right = null; 
         
        return (temp); 
    } 
         
    // Driver code 
    public static void Main() 
    { 
        /* 
                1 
            / 
            2 
            / 
            3 
        */
        Node root = newNode(1); 
        root.left = newNode(2); 
        root.left.left = newNode(3); 
    } 
}

// This code is contributed by AnkitRai01

JavaScript

<script>
// Javascript implementation of above approach

// A Tree node
class Node 
{
    constructor()
    {
        this.key=0;
        this.left=this.right=null;
    }
}

// Utility function to create a new node
function newNode(key)
{
    let temp = new Node();
    temp.key = key;
    temp.left = temp.right = null;
    
    return (temp);
}

// Driver code
 /*
            1
           /
          2
         /
        3
    */
let root = newNode(1);
root.left = newNode(2);
root.left.left = newNode(3);


// This code is contributed by avanitrachhadiya2155
</script>

2. Right Skewed Binary Tree:
These are those skewed binary trees in which all the nodes are having a right child or no child at all. It is a right side dominated tree. All the left children remain as null.

Below is an example of a right-skewed tree:

C++

#include <bits/stdc++.h>
using namespace std;

// A Tree node
struct Node {
    int key;
    struct Node *left, *right;
};

// Utility function to create a new node
Node* newNode(int key)
{
    Node* temp = new Node;
    temp->key = key;
    temp->left = temp->right = NULL;

    return (temp);
}

// Driver code
int main()
{
    /*
        1
         \
          2
           \
            3
    */
    Node* root = newNode(1);
    root->right = newNode(2);
    root->right->right = newNode(3);

    return 0;
}

Java

// Java implementation of above approach
import java.util.*;
class GFG
{
    
// A Tree node
static class Node
{
    int key;
    Node left, right;
};
  
// Utility function to create a new node
static Node newNode(int key)
{
    Node temp = new Node();
    temp.key = key;
    temp.left = temp.right = null;
  
    return (temp);
}
  
// Driver code
public static void main(String args[])
{
    /*
       1
        \
         2
          \
           3
    */
    Node root = newNode(1);
    root.right = newNode(2);
    root.right.right = newNode(3);
}
}

// This code is contributed by Arnab Kundu

Python3

# Python3 implementation of the above approach 

# A Tree node 
class Node: 
    
    def __init__(self, key): 
        
        self.left = None
        self.right = None
        self.val = key 
        
# Driver code
"""         
        1
         \
          2
           \
            3
                 """
root = Node(1)
root.right = Node(2)
root.right.right = Node(3)

# This code is contributed by shivanisinghss2110

// C# implementation of above approach
using System;
 
class GFG
{
      
// A Tree node
public class Node
{
    public int key;
    public Node left, right;
};
    
// Utility function to create a new node
static Node newNode(int key)
{
    Node temp = new Node();
    temp.key = key;
    temp.left = temp.right = null;
    
    return (temp);
}
    
// Driver code
public static void Main(String []args)
{
    /*
       1
        \
         2
          \
           3
    */
    Node root = newNode(1);
    root.right = newNode(2);
    root.right.right = newNode(3);
}
}
 
// This code is contributed by PrinciRaj1992

JavaScript

<script>

// Javascript implementation of above approach

// A Tree node
class Node 
{
    constructor()
    {
        this.key = 0;
        this.left = this.right = null;
    }
}

// Utility function to create a new node
function newNode(key)
{
    let temp = new Node();
    temp.key = key;
    temp.left = temp.right = null;
    
    return(temp);
}

// Driver code
 /*
            1
           /
          2
         /
        3
    */
let root = newNode(1);
root.right = newNode(2);
root.right.right = newNode(3);

// This code is contributed by shivanisinghss2110

</script>

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