Search an element in a Doubly Linked List Last Updated : 04 Sep, 2024 Summarize Comments Improve Suggest changes Share Like Article Like Report Given a Doubly linked list(DLL) containing n nodes and an integer x, the task is to find the position of the integer x in the doubly linked list. If no such position found then print -1.Examples:Input: Linked List = 18 <-> 15 <-> 8 <-> 9 <-> 14, x = 8 Output: 3 Explanation: x= 8 is present at the 3rd node of the doubly linked list. Input: LinkedList = 5 <-> 3 <-> 4 <-> 2 <-> 9, x= 0 Output: -1 Explanation: x = 0 is not present in the doubly linked list. Approach:The idea is to Iterate through the doubly linked list while tracking the position to find the node with value x. If found return the position , otherwise return -1.Follow the steps below to solve the problem:Initialize a variable pos to store the position of the node containing data value x in the doubly linked list.Initialize a pointer curr to store the head node of the doubly linked list.Iterate over the linked list and for every node, check if data value of that node is equal to x or not. If found return pos.return -1 as the node with value x is not present.Below is the implementation of the above approach : C++ //C++ Code for Searching in //Doubly Linked List #include <iostream> using namespace std; class Node { public: int data; Node* next; Node* prev; Node(int new_data) { data = new_data; next = nullptr; prev = nullptr; } }; // Function to find the position of an integer // in a doubly linked list int search(Node* head, int x) { Node* curr = head; int pos = 0; // Traverse the doubly linked list while (curr != nullptr && curr->data != x) { pos++; curr = curr->next; } // If the integer is not present if (curr == nullptr || curr->data != x) return -1; // If the integer is present return (pos + 1); } int main() { Node* head = nullptr; int x = 8; // Create a hard-coded linked list: // 18 <=> 15 <=> 8 <=> 9 <=> 14 head = new Node(18); head->next = new Node(15); head->next->prev = head; head->next->next = new Node(8); head->next->next->prev = head->next; head->next->next->next = new Node(9); head->next->next->next->prev = head->next->next; head->next->next->next->next = new Node(14); head->next->next->next->next->prev = head->next->next->next; cout << search(head, x); return 0; } C // C Code for Searching in Doubly Linked List #include <stdio.h> #include <stdlib.h> struct Node { int data; struct Node* next; struct Node* prev; }; // Function to find the position of an integer // in the doubly linked list int search(struct Node* head, int x) { struct Node* curr = head; int pos = 0; // Traverse the doubly linked list while (curr != NULL && curr->data != x) { pos++; curr = curr->next; } // If the integer is not present in the list if (curr == NULL || curr->data != x) return -1; // If the integer is present in the list return (pos + 1); } struct Node* createNode(int new_data) { struct Node* new_node = (struct Node*)malloc(sizeof(struct Node)); new_node->data = new_data; new_node->next = NULL; new_node->prev = NULL; return new_node; } int main() { struct Node* head = NULL; int x = 8; // Create a hard-coded doubly linked list: // 18 <=> 15 <=> 8 <=> 9 <=> 14 head = createNode(18); head->next = createNode(15); head->next->prev = head; head->next->next = createNode(8); head->next->next->prev = head->next; head->next->next->next = createNode(9); head->next->next->next->prev = head->next->next; head->next->next->next->next = createNode(14); head->next->next->next->next->prev = head->next->next->next; printf("%d\n", search(head, x)); return 0; } Java // Java Code for Searching in // Doubly Linked List class Node { int data; Node next; Node prev; Node(int new_data) { data = new_data; next = null; prev = null; } } public class GfG { // Function to find the position of an integer static int search(Node head, int x) { Node curr = head; int pos = 0; // Traverse the doubly linked list while (curr != null && curr.data != x) { pos++; curr = curr.next; } // If the integer is not present in the list if (curr == null || curr.data != x) return -1; // If the integer is present in the list return (pos + 1); } public static void main(String[] args) { Node head = null; int x = 8; // Create a hard-coded linked list: // 18 <=> 15 <=> 8 <=> 9 <=> 14 head = new Node(18); head.next = new Node(15); head.next.prev = head; head.next.next = new Node(8); head.next.next.prev = head.next; head.next.next.next = new Node(9); head.next.next.next.prev = head.next.next; head.next.next.next.next = new Node(14); head.next.next.next.next.prev = head.next.next.next; System.out.print(search(head, x)); } } Python # Python Code for Searching in Doubly Linked List class Node: def __init__(self, data): self.data = data self.next = None self.prev = None # Function to find the position of an integer # in the doubly linked list def search(head, x): curr = head pos = 0 # Traverse the doubly linked list while curr is not None and curr.data != x: pos += 1 curr = curr.next # If the integer is not present if curr is None or curr.data != x: return -1 # If the integer is present in the list return pos + 1 if __name__ == '__main__': head = None x = 8 # Create a hard-coded linked list: # 18 <=> 15 <=> 8 <=> 9 <=> 14 head = Node(18) head.next = Node(15) head.next.prev = head head.next.next = Node(8) head.next.next.prev = head.next head.next.next.next = Node(9) head.next.next.next.prev = head.next.next head.next.next.next.next = Node(14) head.next.next.next.next.prev = head.next.next.next print(search(head, x)) C# //C# Code for Searching in //Doubly Linked List using System; class Node { public int Data; public Node next; public Node prev; public Node(int data) { Data = data; next = null; prev = null; } } class GfG { // Function to find the position of an integer static int Search(Node head, int x) { Node curr = head; int pos = 0; while (curr != null && curr.Data != x) { pos++; curr = curr.next; } // If the integer is not present in the list if (curr == null || curr.Data != x) return -1; // If the integer is present in the list return pos + 1; } static void Main() { Node head = null; int x = 8; // Create a hard-coded linked list: // 18 <=> 15 <=> 8 <=> 9 <=> 14 head = new Node(18); head.next = new Node(15); head.next.prev = head; head.next.next = new Node(8); head.next.next.prev = head.next; head.next.next.next = new Node(9); head.next.next.next.prev = head.next.next; head.next.next.next.next = new Node(14); head.next.next.next.next.prev = head.next.next.next; Console.WriteLine(Search(head, x)); } } JavaScript // JavaScript Code for Searching // in Doubly Linked List class Node { constructor(data) { this.data = data; this.next = null; this.prev = null; } } // Function to find the position of an integer function search(head, x) { let curr = head; let pos = 0; while (curr !== null && curr.data !== x) { pos++; curr = curr.next; } // If the integer is not present in the list if (curr === null) { return -1; } // If the integer is present in the list return pos + 1; } let head = null; const x = 8; // Create a hard-coded doubly linked list: // 18 <=> 15 <=> 8 <=> 9 <=> 14 head = new Node(14); head.prev = null; head.next = new Node(9); head.next.prev = head; head.next.next = new Node(8); head.next.next.prev = head.next; head.next.next.next = new Node(15); head.next.next.next.prev = head.next.next; head.next.next.next.next = new Node(18); head.next.next.next.next.prev = head.next.next.next; console.log(search(head, x)); Output3Time Complexity: O(n), where n is the number of nodes in the list.Auxiliary Space: O(1). 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