Replace every elements in the array by its frequency in the array

Last Updated : 17 Sep, 2022

Given an array of integers, replace every element by its frequency in the array.

Examples:

Input : arr[] = { 1, 2, 5, 2, 2, 5 }
Output : 1 3 2 3 3 2

Input : arr[] = { 4 5 4 5 6 6 6 }
Output : 2 2 2 2 3 3 3

Approach:

Take a hash map, which will store the frequency of all the elements in the array.
Now, traverse once again.
Now, replace all the elements by their frequency.
Print the modified array.

Implementation:

C++

// C++ program to replace the elements
// by their frequency in the array.
#include "iostream"
#include "unordered_map"
using namespace std;

void ReplaceElementsByFrequency(int arr[], int n)
{
    // Hash map which will store the
    // frequency of the elements of the array.
    unordered_map<int, int> mp;

    for (int i = 0; i < n; ++i) {

        // Increment the frequency
        // of the element by 1.
        mp[arr[i]]++;
    }

    // Replace every element by its frequency
    for (int i = 0; i < n; ++i) {
        arr[i] = mp[arr[i]];
    }
}

int main()
{
    int arr[] = { 1, 2, 5, 2, 2, 5 };
    int n = sizeof(arr) / sizeof(arr[0]);

    ReplaceElementsByFrequency(arr, n);

    // Print the modified array.
    for (int i = 0; i < n; ++i) {
        cout << arr[i] << " ";
    }
    return 0;
}

Java

import java.util.HashMap;

// Java program to replace the elements 
// by their frequency in the array.
class GFG {

    static void ReplaceElementsByFrequency(int arr[], int n) {
        // Hash map which will store the 
        // frequency of the elements of the array. 
        HashMap<Integer, Integer> mp = new HashMap<Integer, Integer>();

        for (int i = 0; i < n; ++i) {

            // Increment the frequency 
            // of the element by 1. 
            if (mp.get(arr[i]) == null) {
                mp.put(arr[i], 1);
            } else {
                mp.put(arr[i], (mp.get(arr[i]) + 1));
            }
            //mp[arr[i]]++; 
        }

        // Replace every element by its frequency 
        for (int i = 0; i < n; ++i) {
            if (mp.get(arr[i]) != null) {
                arr[i] = mp.get(arr[i]);
            }
            //arr[i] = mp[arr[i]]; 
        }
    }

    public static void main(String[] args) {
        int arr[] = {1, 2, 5, 2, 2, 5};
        int n = arr.length;

        ReplaceElementsByFrequency(arr, n);

        // Print the modified array. 
        for (int i = 0; i < n; ++i) {
            System.out.print(arr[i] + " ");
        }
    }
}
// This code contributed by 29AJayKumar

Python3

# Python 3 program to replace the elements
# by their frequency in the array.

def ReplaceElementsByFrequency(arr, n):
    
    # Hash map which will store the
    # frequency of the elements of the array.
    mp = {i:0 for i in range(len(arr))}

    for i in range(n):
        
        # Increment the frequency of the 
        # element by 1.
        mp[arr[i]] += 1

    # Replace every element by its frequency
    for i in range(n):
        arr[i] = mp[arr[i]]

# Driver Code
if __name__ == '__main__':
    arr = [1, 2, 5, 2, 2, 5]
    n = len(arr)

    ReplaceElementsByFrequency(arr, n);

    # Print the modified array.
    for i in range(n):
        print(arr[i], end = " ")

# This code is contributed by
# Sahil_shelangia

// C# program to replace the elements 
// by their frequency in the array.
using System;
using System.Collections.Generic; 
    
class GFG 
{

    static void ReplaceElementsByFrequency(int []arr, int n) 
    {
        // Hash map which will store the 
        // frequency of the elements of the array. 
        Dictionary<int,int> mp = new Dictionary<int,int>();

        for (int i = 0; i < n; ++i)
        {

            // Increment the frequency 
            // of the element by 1. 
            if (!mp.ContainsKey(arr[i])) 
            {
                mp.Add(arr[i], 1);
            } 
            else
            {
                var a = mp[arr[i]] + 1;
                mp.Remove(arr[i]);
                mp.Add(arr[i], a);
            }
        }

        // Replace every element by its frequency 
        for (int i = 0; i < n; ++i) 
        {
            if (mp[arr[i]] != 0) 
            {
                arr[i] = mp[arr[i]];
            }
            //arr[i] = mp[arr[i]]; 
        }
    }

    // Driver code
    public static void Main(String[] args) 
    {
        int []arr = {1, 2, 5, 2, 2, 5};
        int n = arr.Length;

        ReplaceElementsByFrequency(arr, n);

        // Print the modified array. 
        for (int i = 0; i < n; ++i)
        {
            Console.Write(arr[i] + " ");
        }
    }
}

// This code contributed by Rajput-Ji

JavaScript

<script>

// JavaScript program to replace the elements 
// by their frequency in the array.
function ReplaceElementsByFrequency(arr, n) 
{
    
    // Hash map which will store the 
    // frequency of the elements of the array. 
    let mp = new Map();

    for(let i = 0; i < n; ++i)
    {
        
        // Increment the frequency 
        // of the element by 1. 
        if (mp.get(arr[i]) == null)
        {
            mp.set(arr[i], 1);
        } 
        else
        {
            mp.set(arr[i], (mp.get(arr[i]) + 1));
        }
        //mp[arr[i]]++; 
    }

    // Replace every element by its frequency 
    for(let i = 0; i < n; ++i) 
    {
        if (mp.get(arr[i]) != null) 
        {
            arr[i] = mp.get(arr[i]);
        }
        //arr[i] = mp[arr[i]]; 
    }
}

// Driver Code
let arr = [ 1, 2, 5, 2, 2, 5 ];
let n = arr.length;

ReplaceElementsByFrequency(arr, n);

// Print the modified array. 
for(let i = 0; i < n; ++i)
{
    document.write(arr[i] + " ");
}

// This code is contributed by code_hunt

</script>

Output

1 3 2 3 3 2

Time Complexity: O(N)

Auxiliary Space: O(N) because extra space is being used for unordered_map mp

Replace every elements in the array by its frequency in the array

imdhruvgupta

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Replace every elements in the array by its frequency in the array

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