Removing elements between the two zeros
Last Updated :
07 Oct, 2022
Given an integer N which shows the size of the string and in the next line given a string which contains a string of character with only zero and one. The task is to remove a single character each time that comes in between the two zero characters.
During each turn, only one character from the string will be removed that satisfies the following condition :
- It must be surrounded by zeroes on both sides.
Examples:
Input : str = "1001
Output : str = "1001"
Input : str = "10101
Output : str = "1001"
Use a loop from 1 to N - 1 and check if any element lies between two zeros such that s[i - 1] = '0' and s[i + 1] = '0'. If the condition is satisfied then, delete the character at that position, ad start searching for patterns again.
C++
// C++ program to delete elements between zeros
#include <bits/stdc++.h>
using namespace std;
// Function to find the string
// after operation
string findstring(string s)
{
int n = s.length();
// Traversing through string
for (int i = 1; i < n - 1; i++)
{
// Checking for character
// Between two zeros
if ((s.at(i - 1) == '0' &&
s.at(i + 1) == '0'))
{
// deleting the character
// At specific position
s.erase(i, 1);
i--;
if (i > 0 && s.at(i - 1) == '0')
i--;
// updating the length
// of the string
n = s.length();
}
}
return s;
}
// Drivers code
int main() {
cout << findstring("100100");
return 0;
}
// Java program to delete elements between zeros
import java.util.*;
public class GFG
{
// Function to find the string
// after operation
static String findstring(String s)
{
int n = s.length();
// use for loop to remove the
// character between two zeros
for (int i = 1; i < n - 1; i++)
{
// Checking for character
// Between two zeros
if ((s.charAt(i - 1) == '0' &&
s.charAt(i + 1) == '0'))
{
// deleting the character
// At specific position
s = s.substring(0, i) + s.substring(i + 1);
i--;
if (i > 0 && s.charAt(i - 1) == '0')
i--;
// updating the length
// of the string
n = s.length();
}
}
return s;
}
// Driver code
public static void main(String[] args)
{
String s="100100";
System.out.println(findstring(s));
}
}
# Python3 program to delete elements
# between zeros
# Function to find the string
# after operation
def findstring(s):
n = len(s)
s = list(s)
i = 1
# Traversing through string
while i < n - 1:
# Checking for character
# Between two zeros
if (s[i - 1] == '0' and
s[i + 1] == '0'):
# Deleting the character
# At specific position
s.pop(i)
i -= 1
if i > 0 and s[i - 1] == '0':
i -= 1
# Updating the length
# of the string
n = len(s)
i += 1
return ''.join(s)
# Driver code
if __name__ == '__main__':
print (findstring('100100'))
# This code is contributed by rutvik_56
// C# program to delete
// elements between zeros
using System;
class GFG
{
// Function to find the
// string after operation
static string findstring(string s)
{
int n = s.Length;
string st = "";
// Traversing through string
for (int i = 1; i < n - 1; i++)
{
// Checking for character
// Between two zeros
if ((s[i - 1] == '0' &&
s[i + 1] == '0'))
{
// deleting the character
// At specific position
st = s.Remove(i, 1);
s = st;
i--;
if (i > 0 &&
s[i - 1] == '0')
i--;
// updating the length
// of the string
n = s.Length;
}
}
return s;
}
// Driver code
static void Main()
{
Console.Write(findstring("100100"));
}
}
// This code is contributed by
// Manish Shaw(manishshaw1)
<script>
// JavaScript program to delete elements
// between zeros
// Function to find the string
// after operation
function findstring(s){
let n = s.length
s = s.split('')
let i = 1
// Traversing through string
while(i < n - 1){
// Checking for character
// Between two zeros
if (s[i - 1] == '0' && s[i + 1] == '0'){
// Deleting the character
// At specific position
s.splice(i,1);
i -= 1
if(i > 0 && s[i - 1] == '0')
i -= 1
// Updating the length
// of the string
n = s.length
}
i += 1
}
return s.join('')
}
// Driver code
document.write(findstring('100100'),"</br>")
// This code is contributed by shinjanpatra
</script>
Time Complexity: O(N2), where N is the size of the input string and using erase function to delete the value in the string.
Auxiliary Space: O(1)
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