C Pointer Basics

Consider the following declaration:

int a, *b=&a, **c=&b;

The following program fragment

a=4;
**c=5;

Consider the following C program. 

#include<stdio.h>
void mystery(int *ptra, int *ptrb) 
{
   int *temp;
   temp = ptrb;
   ptrb = ptra;
   ptra = temp;
}
int main() 
{
    int a=2016, b=0, c=4, d=42;
    mystery(&a, &b);
    if (a < c)
       mystery(&c, &a);
    mystery(&a, &d);
    printf("%d", a);
}

The output of the program _____________   Note : This question was asked as Numerical Answer Type.

int main()
{
    int array[5][5];
    printf("%d",( (array == *array) && (*array == array[0]) ));
    return 0;    
}

int main()
{
   int a = 300;    
   char *b = (char *)&a;
   *++b = 2;
   printf("%d ",a);
   return 0;
}

Consider the following function implemented in C:

void printxy(int x, int y)
{
    int *ptr;
    x = 0;
    ptr = &x;
    y = *ptr;
    *ptr = 1;
    printf("%d,%d", x, y);
}

The output of the printxy(1,1) is

Consider the following snippet of a C program. Assume that swap(&x, &y) exchanges the contents of x and y.

int main()
{
    int array[] = {3, 5, 1, 4, 6, 2};
    int done = 0;
    int i;

    while (done == 0)
    {
        done  = 1;
        for (i = 0; i <= 4; i++)
        {
            if (array[i] < array[i+1])
            {
                swap(&array[i], &array[i+1]);
                done = 0;
            }
        }
        for (i = 5; i >= 1; i--)
        {
            if (array[i] > array[i-1])
            {
                swap(&array[i], &array[i-1]);
                done = 0;
            }
        }
    }

    printf("%d", array[3]);
}

The output of the program is _____. Note: This question appeared as Numerical Answer Type.

‘ptrdata’ is a pointer to a data type. The expression *ptrdata++ is evaluated as (in C++) :
 

Consider the following table

Matching A, B, C, D in the same order gives :

What does the following C-statement declare? int (*f) (int*);