Python program to count Even and Odd numbers in a Dictionary

# Python3 Program to count even and
# odd numbers present in a dictionary

# Function to count even and odd
# numbers present in a dictionary
def countEvenOdd(dict):
    
    # Stores count of even
    # and odd elements
    even = 0
    odd = 0
    
    # Traverse the dictionary
    for i in dict.values():
      
      if i % 2 == 0:
        even = even + 1
      else:
        odd = odd + 1
        
    print("Even Count: ", even)
    print("Odd Count: ", odd)

# Driver Code

dict = {'a': 1, 'b': 2, 'c': 3, 'd': 4, 'e': 5}
countEvenOdd(dict)

# Python3 Program to count even
# and odd elements in a dictionary

# Function to count even and
# odd elements in a dictionary
def countEvenOdd(dict):
  even = 0
  odd = 0
  
  # Iterate over the dictionary
  for i in dict:
    
    # If current element is even
    if dict[i] % 2 == 0:
      
      # Increase count of even
      even = even + 1
      
    # Otherwise
    else:
      
      # Increase count of odd
      odd = odd + 1
      
  print("Even count: ", even)
  print("Odd count: ", odd)
    
# Driver Code

# Given Dictionary
dict = {'a': 1, 'b': 2, 'c': 3, 'd': 4, 'e': 5}

countEvenOdd(dict)

# Python3 Program to count even
# and odd elements in a dictionary 
#using bitwise operator

def fun1(x):
    if(x&1!=0): # Using bitwise opearor
        return x
# Given Dictionary
dict = {'a': 1, 'b': 2, 'c': 3, 'd': 4, 'e': 5}
x=list(dict.values())
y=filter(fun1,x)
odd=len(list(y))
even=len(x)-odd
print("Even count: ", even)
print("Odd count: ", odd)

#This code contributed by vinay pinjala.

# Python3 Program to count even
# and odd elements in a dictionary

def fun1(x):
    if(x%2==0):
        return x
# Given Dictionary
dict = {'a': 1, 'b': 2, 'c': 3, 'd': 4, 'e': 5}
x=list(dict.values())
y=filter(fun1,x)
even=len(list(y))
odd=len(x)-even
print("Even count: ", even)
print("Odd count: ", odd)