Python | Elements with Frequency equal K

# Python3 code to demonstrate 
# Elements with Frequency equal K
# using naive method

# initializing list
test_list = [9, 4, 5, 4, 4, 5, 9, 5]

# printing original list
print ("Original list : " + str(test_list))

# initializing K 
K = 3

# using naive method to 
# get most frequent element
res = []
for i in test_list:
    freq = test_list.count(i)
    if freq == K and i not in res:
        res.append(i)
    
# printing result
print ("Elements with count K are : " + str(res))

# Python3 code to demonstrate
# Elements with Frequency equal K
# using Counter() function
from collections import Counter

# initializing list
test_list = [9, 4, 5, 4, 4, 5, 9, 5]

# printing original list
print("Original list : " + str(test_list))

# initializing K
K = 3
res = []
freq = Counter(test_list)
for key, value in freq.items():
    if(value == K):
        res.append(key)
# printing result
print("Elements with count K are : " + str(res))

# Python3 code to demonstrate
# Elements with Frequency equal K

import operator as op
# initializing list
test_list = [9, 4, 5, 4, 4, 5, 9, 5]

# printing original list
print("Original list : " + str(test_list))

# initializing K
K = 3
res = []
unique_elements = set(test_list)
for i in unique_elements:
    if op.countOf(test_list, i) == K:
        res.append(i)
# printing result
print("Elements with count K are : " + str(res))