Open In App

Program to find the mid-point of a line

Last Updated : 20 Feb, 2023
Comments
Improve
Suggest changes
Like Article
Like
Report

Given two coordinates of a line starting is (x1,y1) and ending is (x2,y2) find out the mid-point of a line. 
Examples : 
 

Input  : x1 = –1, y1 = 2, 
         x2 = 3, y2 = –6
Output : 1,–2

Input  : x1 = 6.4, y1 = 3 
         x2 = –10.7, y2 = 4
Output : –2.15, 3.5


 


 


The Midpoint Formula: The midpoint of two points, (x1, y2) and (x2, y2) is the point M found by the following formula: M = ((x1+x2)/2 , (y1+y2)/2)
 

C++
// C++ program to find 
// the midpoint of a line
#include<iostream>
using namespace std;

// function to find the
// midpoint of a line
void midpoint(int x1, int x2,
                int y1, int y2)
{
    cout << (float)(x1+x2)/2 << 
            " , "<< (float)(y1+y2)/2 ; 
}

// Driver Function to test above
int main()
{
    int x1 =-1, y1 = 2  ;
    int x2 = 3, y2 = -6 ;    
    midpoint(x1, x2, y1, y2);    
    return 0;
}
Java
// Java program to find 
// the midpoint of a line
import java.io.*;

class GFG 
{
    // function to find the
    // midpoint of a line
    static void midpoint(int x1, int x2,
                          int y1, int y2)
    {
        System.out.print((x1 + x2) / 2 +
                        " , " + (y1 + y2) / 2) ; 
    }

    // Driver code
    public static void main (String[] args) 
    {
        int x1 =-1, y1 = 2 ;
        int x2 = 3, y2 = -6 ; 
        midpoint(x1, x2, y1, y2);
            
    }
}

// This code is contributed by vt_m.
Python3
 
# Python3 program to find 
# the midpoint of a line

# Function to find the
# midpoint of a line
def midpoint(x1, x2, y1, y2):

    print((x1 + x2) // 2, " , ",
                 (y1 + y2) // 2) 
 
# Driver Code
x1, y1, x2, y2 = -1, 2, 3, -6
midpoint(x1, x2, y1, y2)

# This code is contributed by Anant Agarwal.
C#
// C# program to find 
// the midpoint of a line
using System;

class GFG 
{
    // function to find the
    // midpoint of a line
    static void midpoint(int x1, int x2,
                        int y1, int y2)
    {
        Console.WriteLine((x1 + x2) / 2 +
                        " , " + (y1 + y2) / 2) ; 
    }

    // Driver code
    public static void Main () 
    {
        int x1 =-1, y1 = 2 ;
        int x2 = 3, y2 = -6 ; 
        
        midpoint(x1, x2, y1, y2);
            
    }
}

// This code is contributed by vt_m.
PHP
<?php
// PHP program to find 
// the midpoint of a line

// function to find the
// midpoint of a line
function midpoint($x1, $x2, $y1, $y2)
{
    echo((float)($x1 + $x2)/2 . " , " .
                (float)($y1 + $y2)/2) ; 
}

// Driver Code
$x1 = -1; $y1 = 2 ;
$x2 = 3; $y2 = -6 ;     
midpoint($x1, $x2, $y1, $y2); 

// This code is contributed by Ajit.
?>
JavaScript
<script>

// JavaScript program to find 
// the midpoint of a line

// function to find the
    // midpoint of a line
    function midpoint(x1, x2,
                          y1, y2)
    {
        document.write((x1 + x2) / 2 +
                        " , " + (y1 + y2) / 2) ; 
    }

// Driver code
        
        let x1 =-1, y1 = 2 ;
        let x2 = 3, y2 = -6 ; 
        midpoint(x1, x2, y1, y2);
                  
</script>

Output : 

1 , -2

Time complexity: O(1) since performing only constant operations

Auxiliary Space: O(1)


 


Next Article
Practice Tags :

Similar Reads