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Print the last occurrence of elements in array in relative order

Last Updated : 31 Aug, 2022
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Given an array of N elements, print the elements in the same relative order as given by removing all the occurrences of elements except the last occurrence. 

Examples

Input: a[] = {1, 5, 5, 1, 6, 1} 
Output: 5 6 1 
Remove two integers 1, which are in the positions 1 and 4. Also, remove the integer 5, which is in the position 2. 
Hence the left array is {5, 6, 1}

Input: a[] = {2, 5, 5, 2} 
Output: 5 2 

Approach: 

  • Hash the last occurrence of every element.
  • Iterate in the array of N elements, if the element's index is hashed, then print the array element.

Below is the implementation of the above approach: 

C++
// C++ program to print the last occurrence
// of every element in relative order
#include <bits/stdc++.h>
using namespace std;

// Function to print the last occurrence
// of every element in an array
void printLastOccurrence(int a[], int n)
{

    // used in hashing
    unordered_map<int, int> mp;

    // iterate and store the last index
    // of every element
    for (int i = 0; i < n; i++)
        mp[a[i]] = i;

    // iterate and check for the last
    // occurrence of every element
    for (int i = 0; i < n; i++) {
        if (mp[a[i]] == i)
            cout << a[i] << " ";
    }
}
// Driver Code
int main()
{
    int a[] = { 1, 5, 5, 1, 6, 1 };
    int n = sizeof(a) / sizeof(a[0]);
    printLastOccurrence(a, n);

    return 0;
}
Java
// Java program to print the 
// last occurrence of every 
// element in relative order
import java.util.*;

class GFG
{
    
    // Function to print the last 
    // occurrence of every element
    // in an array
    public static void printLastOccurrence(int a[],
                                           int n)
    {
        HashMap<Integer, 
                Integer> map = new HashMap<Integer, 
                                           Integer>();
        
        // iterate and store the last 
        // index of every element
        for (int i = 0; i < n; i++)
            map.put(a[i], i);
            
        for (int i = 0; i < n; i++)
        {
        if (map.get(a[i]) == i)
            System.out.print(a[i] +" ");
        } 
    }
    
    // Driver Code
    public static void main (String[] args)
    {
        int a[] = { 1, 5, 5, 1, 6, 1 };
        int n = a.length;
        printLastOccurrence(a, n);
    }
}

// This code is contributed
// by ankita_saini
Python3
# Python 3 program to print the last occurrence
# of every element in relative order

# Function to print the last occurrence
# of every element in an array
def printLastOccurrence(a, n):
    
    # used in hashing
    mp = {i:0 for i in range(7)}

    # iterate and store the last 
    # index of every element
    for i in range(n):
        mp[a[i]] = i

    # iterate and check for the last
    # occurrence of every element
    for i in range(n):
        if (mp[a[i]] == i):
            print(a[i], end = " ")

# Driver Code
if __name__ == '__main__':
    a = [1, 5, 5, 1, 6, 1]
    n = len(a)
    printLastOccurrence(a, n)

# This code is contributed by
# Surendra_Gangwar
C#
// C# program to print the 
// last occurrence of every 
// element in relative order
using System;

class GFG
{
    
// Function to print the last 
// occurrence of every element
// in an array
public static void printLastOccurrence(int[] a,
                                       int n)
{
    HashMap<Integer, 
            Integer> map = new HashMap<Integer, 
                                       Integer>();
    
    // iterate and store the last 
    // index of every element
    for (int i = 0; i < n; i++)
        map.put(a[i], i);
        
    for (int i = 0; i < n; i++)
    {
    if (map.get(a[i]) == i)
        Console.Write(a[i] + " ");
    } 
}

// Driver Code
public static void Main ()
{
    int[] a = { 1, 5, 5, 1, 6, 1 };
    int n = a.Length;
    printLastOccurrence(a, n);
}
}

// This code is contributed
// by ChitraNayal
PHP
<?php 
// PHP program to print the last 
// occurrence of every element 
// in relative order

// Function to print the last
// occurrence of every element
// in an array
function printLastOccurrence(&$a, $n)
{

    // used in hashing
    $mp = array();

    // iterate and store the last 
    // index of every element
    for ($i = 0; $i < $n; $i++)
        $mp[$a[$i]] = $i;

    // iterate and check for the last
    // occurrence of every element
    for ($i = 0; $i < $n; $i++) 
    {
        if ($mp[$a[$i]] == $i)
            echo $a[$i] . " ";
    }
}

// Driver Code
$a = array(1, 5, 5, 1, 6, 1);
$n = sizeof($a);
printLastOccurrence($a, $n);

// This code is contributed 
// by ChitraNayal
?>
JavaScript
<script>

// Javascript program to print the last
// occurrence of every element
// in relative order

// Function to print the last
// occurrence of every element
// in an array
function printLastOccurrence(a, n)
{

    // used in hashing
    let mp = [];

    // iterate and store the last
    // index of every element
    for (let i = 0; i < n; i++)
        mp[a[i]] = i;

    // iterate and check for the last
    // occurrence of every element
    for (let i = 0; i < n; i++)
    {
        if (mp[a[i]] == i)
            document.write( a[i] + " ");
    }
}

// Driver Code
let a = [1, 5, 5, 1, 6, 1];
let n = a.length;
printLastOccurrence(a, n);


// This code is contributed by sravan kumar

</script>

Output
5 6 1 

Complexity Analysis:

  • Time Complexity: O(N)
  • Auxiliary Space: O(N)

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