Print n numbers such that their sum is a perfect square Last Updated : 20 Dec, 2022 Comments Improve Suggest changes Like Article Like Report Given an integer n, the task is to print n numbers such that their sum is a perfect square.Examples: Input: n = 3 Output: 1 3 5 1 + 3 + 5 = 9 = 32 Input: n = 4 Output: 1 3 5 7 1 + 3 + 5 + 7 = 16 = 42 Approach: The sum of first n odd numbers is always a perfect square. So, we will print the first n odd numbers as the output.Below is the implementation of the above approach: C++ // C++ implementation of the approach #include <bits/stdc++.h> using namespace std; // Function to print n numbers such that // their sum is a perfect square void findNumbers(int n) { int i = 1; while (i <= n) { // Print ith odd number cout << ((2 * i) - 1) << " "; i++; } } // Driver code int main() { int n = 3; findNumbers(n); } Java // Java implementation of the approach import java.util.*; import java.io.*; class GFG { // Function to print n numbers such that // their sum is a perfect square static void findNumbers(int n) { int i = 1; while (i <= n) { // Print ith odd number System.out.print(((2 * i) - 1) + " "); i++; } } // Driver code public static void main(String args[]) { int n = 3; findNumbers(n); } } Python3 # Python3 implementation of the approach # Function to print n numbers such that # their sum is a perfect square def findNumber(n): i = 1 while i <= n: # Print ith odd number print((2 * i) - 1, end = " ") i += 1 # Driver code n = 3 findNumber(n) # This code is contributed by Shrikant13 C# // C# implementation of the approach using System; public class GFG { // Function to print n numbers such that // their sum is a perfect square public static void findNumbers(int n) { int i = 1; while (i <= n) { // Print ith odd number Console.Write(((2 * i) - 1) + " "); i++; } } // Driver code public static void Main(string[] args) { int n = 3; findNumbers(n); } } // This code is contributed by Shrikant13 PHP <?php // PHP implementation of the approach // Function to print n numbers such that // their sum is a perfect square function findNumbers($n) { $i = 1; while ($i <= $n) { // Print ith odd number echo ((2 * $i) - 1) . " "; $i++; } } // Driver code $n = 3; findNumbers($n); // This code contributed by PrinciRaj1992 ?> JavaScript <script> // JavaScript implementation of the approach // Function to print n numbers such that // their sum is a perfect square function findNumbers(n) { var i = 1; while (i <= n) { // Print ith odd number document.write(((2 * i) - 1)+" ") ; i++; } } var n = 3; findNumbers(n); </script> Output1 3 5 Time Complexity: O(N), as we are using a loop to traverse N times so it will cost us O(N) time.Auxiliary Space: O(1), as we are not using any extra space. Comment More infoAdvertise with us Next Article Analysis of Algorithms S spp____ Follow Improve Article Tags : Mathematical DSA number-theory maths-perfect-square Practice Tags : Mathematicalnumber-theory Similar Reads Basics & PrerequisitesLogic Building ProblemsLogic building is about creating clear, step-by-step methods to solve problems using simple rules and principles. 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