Output of python program | Set 12(Lists and Tuples)
Last Updated :
11 Mar, 2022
Prerequisite: List and Tuples
Note: Output of all these programs is tested on Python3
1) What is the output of the following program?
PYTHON
L1 = []
L1.append([1, [2, 3], 4])
L1.extend([7, 8, 9])
print(L1[0][1][1] + L1[2])
|
a) Type Error: can only concatenate list (not “int”) to list
b) 12
c) 11
d) 38
Ans: (c)
Explanation: In the print(), indexing is used. L1[0] denotes [1, [2, 3], 4], L1[0][1] denotes [2, 3],
L1[0][1][1] = 3 and L1[2] = 8. Thus, the two integers are added, 3 + 8 = 11 and output comes as 11.
2) What is the output of the following program?
PYTHON
L1 = [1, 1.33, 'GFG', 0, 'NO', None, 'G', True]
val1, val2 = 0, ''
for x in L1:
if(type(x) == int or type(x) == float):
val1 += x
else if(type(x) == str):
val2 += x
else:
break
print(val1, val2)
|
a) 2 GFGNO
b) 2.33 GFGNOG
c) 2.33 GFGNONoneGTrue
d) 2.33 GFGNO
Ans: (d)
Explanation: val1 will only have integer and floating values val1 = 1 + 1.33 + 0 = 2.33 and val2 will have string
values val2 ='GFG' + 'NO' = 'GFGNO'. String 'G' will not be part of val2 as the for loop will break at None,
thus 'G' will not be added to val2.
3) What is the output of the following program?
Python3
L1 = [1, 2, 3, 4]
L2 = L1
L3 = L1.copy()
L4 = L3
L1[0] = [5]
print(L1, L2, L3, L4)
|
a) [5, 2, 3, 4] [5, 2, 3, 4] [1, 2, 3, 4] [1, 2, 3, 4]
b) [[5], 2, 3, 4] [[5], 2, 3, 4] [[5], 2, 3, 4] [1, 2, 3, 4]
c) [5, 2, 3, 4] [5, 2, 3, 4] [5, 2, 3, 4] [1, 2, 3, 4]
d) [[5], 2, 3, 4] [[5], 2, 3, 4] [1, 2, 3, 4] [1, 2, 3, 4]
Ans: (d)
Explanation: L2 is the reference pointing to the same object as L1,
while L3 and L4 are single recursive Copy(Shallow Copy) of List L1.
L1[0] = [5], implies that at index 0, list [5] will be present and not integer value 5.
4) What is the output of the following program?
PYTHON
import sys
L1 = tuple()
print(sys.getsizeof(L1), end = " ")
L1 = (1, 2)
print(sys.getsizeof(L1), end = " ")
L1 = (1, 3, (4, 5))
print(sys.getsizeof(L1), end = " ")
L1 = (1, 2, 3, 4, 5, [3, 4], 'p', '8', 9.777, (1, 3))
print(sys.getsizeof(L1))
|
a) 0 2 3 10
b) 32 34 35 42
c) 48 64 72 128
d) 48 144 192 480
Ans: (c)
Explanation: An Empty Tuple has 48 Bytes as Overhead size and each additional element requires 8 Bytes.
(1, 2) Size: 48 + 2 * 8 = 64
(1, 3, (4, 5)) Size: 48 + 3 * 8 = 72
(1, 2, 3, 4, 5, [3, 4], 'p', '8', 9.777, (1, 3)) Size: 48 + 10 * 8 = 128
5) What is the output of the following program?
PYTHON
T1 = (1)
T2 = (3, 4)
T1 += 5
print(T1)
print(T1 + T2)
|
a) TypeError
b) (1, 5, 3, 4)
c) 1 TypeError
d) 6 TypeError
Ans: (d)
Explanation: T1 is an integer while T2 is tuple. Thus T1 will become 1 + 5 = 6. But an integer and tuple cannot be added, it will throw TypeError.
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