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numpy.ma.choose() function - Python

Last Updated : 05 May, 2020

numpy.ma.choose() function use an index array to construct a new array from a set of choices. Given an array of integers and a set of n choice arrays, this method will create a new array that merges each of the choice arrays. Where arr value in arr is i, the new array will have the value that choices[i] contains in the same place.

Syntax : numpy.ma.choose(arr, choices, out = None, mode = 'raise') Parameters : arr : [ndarray of ints] This array must contain integers in [0, n-1], where n is the number of choices. choices : [sequence of arrays] Choice arrays. The index array and all of the choices should be broadcastable to the same shape. out : [array, optional] If provided, the result will be inserted into this array. It should be of the appropriate shape and dtype. mode : [{‘raise’, ‘wrap’, ‘clip’}, optional] Specifies how out-of-bounds indices will behave. ‘raise’: raise an error. ‘wrap’: wrap around. ‘clip’: clip to the range. Return : A new array that merges each of the choice arrays.

Code #1 :

Python3

# Python program explaining
# numpy.ma.choose() function
  
# importing numpy as geek   
# and numpy.ma module as ma  
import numpy as geek  
import numpy.ma as ma
 
choice = geek.array([[1, 1, 1], [2, 2, 2], [3, 3, 3]])
arr = geek.array([2, 1, 0])

gfg = geek.ma.choose(arr, choice)

print (gfg)

Output :

[3 2 1]

Code #2 :

Python3

# Python program explaining
# numpy.ma.choose() function
  
# importing numpy as geek   
# and numpy.ma module as ma  
import numpy as geek  
import numpy.ma as ma
 
choice = geek.array([[1, 1, 1], [2, 2, 2], [3, 3, 3]])
arr = geek.array([0, 1, 2])

gfg = geek.ma.choose(arr, choice)

print (gfg)

Output :

[1 2 3]

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