Step 1: Use the formula 6n + 1 or 6n − 1 to find if 29 fits.
Step 2: For n = 5, 6 × 5 − 1 = 29.
Step 3: Since 29 fits the 6n − 1 form, it could be prime.
Step 4: Now, check divisibility by smaller primes (2, 3, 5). Since 29 is not divisible by any of these, it is confirmed to be a prime number.
For n = 0, 02 + 0 + 41 = 41, which is prime.
For n = 1, 12 + 1 + 41 = 43, which is prime.
For n = 2, 22 + 2 + 41 = 47, which is prime.
For n = 3, 32 + 3 + 41 = 53, which is prime
Step 1: Find the square root of 77.
The approximate square root of 77 is ≈ 8.77. This means we only need to check divisibility by the prime numbers less than or equal to 8 (i.e., 2, 3, 5, and 7).
Step 2: Check divisibility by 2.
77 is odd, so it is not divisible by 2.
Step 3: Check divisibility by 3.
The sum of the digits of 77 is 7+7=147 + 7 = 147+7=14, which is not divisible by 3. Therefore, 77 is not divisible by 3.
Step 4: Check divisibility by 5.
Since 77 does not end in 0 or 5, it is not divisible by 5.
Step 5: Check divisibility by 7.
77 ÷ 7 = 11. Since 77 is divisible by 7, it has a divisor other than 1 and itself.
So 77 is not a prime number, as it has divisors other than 1 and itself