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Double Angle Formula for Cosine

Last Updated : 23 Jul, 2025
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Double angle formula for cosine is a trigonometric identity that expresses cos⁡(2θ) in terms of cos⁡(θ) and sin⁡(θ) the double angle formula for cosine is, cos 2θ = cos2θ - sin2θ. The formula is particularly useful in simplifying trigonometric expressions and solving equations involving trigonometric functions.

In this article, we will learn about, Double Angle Formula for Cosine, Double Angle Formula for Cosine Derivation, Double Angle Formula for Cosine Examples and others.

Cos Double Angle Formulas

In trigonometry, cos 2x is a double-angle identity. Because the cos function is a reciprocal of the secant function, it may also be represented as cos 2x = 1/sec 2x. It's a significant trigonometric identity that may be used for a variety of trigonometric and integration problems. The value of cos 2x repeats after every π radians, cos 2x = cos (2x + π). It has a considerably narrower graph than cos x. It's a trigonometric function that returns the cos function value of a double angle.

Cos-Double-Angle-Formula
Cos Double Angle Formulas

The cos double angle formula can be simplified further by using sine cosine identity and that is:

cos 2x = cos2 x - sin2 x

Putting sin2 x = 1 - cos2 x, the formula becomes,

cos 2x = cos2 x - (1 - cos2 x)

cos 2x = 2 cos2 x - 1

Putting cos2 x = 1 - sin2 x, the formula becomes,

cos 2x = (1 - sin2 x) - sin2 x

cos 2x = 1 - 2 sin2 x

Derivation of Double Angle Formula for Cosine

Formula for cos 2x can be derived by using the sum angle formula for cosine function.

We already know, cos (A + B) = cos A cos B - sin A sin B

To calculate the value of cosine double angle, the angle A must be equal to angle B.

Putting A = B we get,

cos (A + A) = cos A cos A - sin A sin A

cos 2A = cos2 A - sin2 A

This derives the formula for double angle of cosine ratio.

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Sample Problems on Double Angle Formulas for Cosine

Problem 1. If cos x = 3/5, find the value of cos 2x using the formula.

Solution:

We have, cos x = 3/5

Clearly, sin x = 4/5

Using the formula we get,

cos 2x = cos2 x - sin2 x

= (3/5)2 - (4/5)2

= 9/25 - 16/25

= -7/25

Problem 2. If cos x = 12/13, find the value of cos 2x using the formula.

Solution:

We have, cos x = 12/13

Clearly, sin x = 5/13

Using the formula we get,

cos 2x = cos2 x - sin2 x

= (12/13)2 - (5/13)2

= 144/169 - 25/169

= 119/169

Problem 3. If sin x = 3/5, find the value of cos 2x using the formula.

Solution:

We have, sin x = 3/5

Clearly cos x = 4/5

Using the formula we get,

cos 2x = cos2 x - sin2 x

= (4/5)2 - (3/5)2

= 16/25 - 9/25

= 7/25

Problem 4. If tan x = 12/5, find the value of cos 2x using the formula.

Solution:

We have, tan x = 12/5

Clearly sin x = 12/13 and cos x = 5/13

Using the formula we get,

cos 2x = cos2 x - sin2 x

= (5/13)2 - (12/13)2

= 25/169 - 144/169

= -119/169

Problem 5. If sec x = 17/8, find the value of cos 2x using the formula.

Solution:

We have, sec x = 17/8

Clearly cos x = 8/17 and sin x = 15/17

Using the formula we get,

cos 2x = cos2 x - sin2 x

= (8/17)2 - (15/17)2

= 64/289 - 225/289

= -161/289

Problem 6. If cot x = 15/8, find the value of cos 2x using the formula.

Solution:

We have, cot x = 15/8

Clearly cos x = 15/17 and sin x = 8/17

Using the formula we get,

cos 2x = cos2 x - sin2 x

= (15/17)2 - (8/17)2

= 225/289 - 64/289

= 161/289

Problem 7. If cos2 x = 5/8, find the value of cos 2x using the formula.

Solution:

We have,

cos2 x = 5/8

Using the formula we get,

cos 2x = 2 cos2 x - 1

= 2 (5/8) - 1

= 5/4 - 1

= 1/4

Problem 8. If sin2 x = 6/7, find the value of cos 2x using the formula.

Solution:

We have,

sin2 x = 6/7

Using the formula we get,

cos 2x = 1 - 2 sin2

= 1 - 2 (6/7)

= 1 - 12/7

= -5/7


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