Javascript Program For Sorting Linked List Which Is Already Sorted On Absolute Values
Last Updated :
03 Sep, 2024
Given a linked list that is sorted based on absolute values. Sort the list based on actual values.
Examples:
Input: 1 -> -10
Output: -10 -> 1
Input: 1 -> -2 -> -3 -> 4 -> -5
Output: -5 -> -3 -> -2 -> 1 -> 4
Input: -5 -> -10
Output: -10 -> -5
Input: 5 -> 10
Output: 5 -> 10
Source : Amazon Interview
A simple solution is to traverse the linked list from beginning to end. For every visited node, check if it is out of order. If it is, remove it from its current position and insert it at the correct position. This is the implementation of insertion sort for linked list and the time complexity of this solution is O(n*n).
A better solution is to sort the linked list using merge sort. Time complexity of this solution is O(n Log n).
An efficient solution can work in O(n) time. An important observation is, all negative elements are present in reverse order. So we traverse the list, whenever we find an element that is out of order, we move it to the front of the linked list.
Below is the implementation of the above idea.
ever we find an element that is out of order, we move it to the front of the linked list.
Below is the implementation of the above idea.
JavaScript
// Javascript program to sort a linked list,
// already sorted by absolute values
// head of list
let head;
// Linked list Node
class Node {
constructor(d) {
this.data = d;
this.next = null;
}
}
// To sort a linked list by actual values.
// The list is assumed to be sorted by
// absolute values.
function sortedList(head) {
// Initialize previous and current
// nodes
let prev = head;
let curr = head.next;
// Traverse list
while (curr != null) {
// If curr is smaller than prev, then
// it must be moved to head
if (curr.data < prev.data) {
// Detach curr from linked list
prev.next = curr.next;
// Move current node to beginning
curr.next = head;
head = curr;
// Update current
curr = prev;
}
// Nothing to do if current element
// is at right place
else
prev = curr;
// Move current
curr = curr.next;
}
return head;
}
/* Inserts a new Node at front of
the list. */
function push(new_data) {
/* 1 & 2: Allocate the Node &
Put in the data */
let new_node = new Node(new_data);
// 3. Make next of new Node as head
new_node.next = head;
// 4. Move the head to point to
// new Node
head = new_node;
}
// Function to print linked list
function printList(head) {
let temp = head;
while (temp != null) {
console.log(temp.data);
temp = temp.next;
}
}
// Driver code
/* Constructed Linked List is
1->2->3->4->5->6-> 7->8->8->
9->null */
push(-5);
push(5);
push(4);
push(3);
push(-2);
push(1);
push(0);
console.log("Original List :");
printList(head);
head = sortedList(head);
console.log("Sorted list :");
printList(head);
// This code is contributed by aashish1995
Output:
Original list :
0 -> 1 -> -2 -> 3 -> 4 -> 5 -> -5
Sorted list :
-5 -> -2 -> 0 -> 1 -> 3 -> 4 -> 5
Complexity Analysis:
- Time Complexity: O(N)
- Auxiliary Space: O(1)
Please refer complete article on Sort linked list which is already sorted on absolute values for more details!
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