How to Find Sum of Squares from Standard Deviation?
Last Updated :
28 Aug, 2024
Answer: To find the sum of squares from the standard deviation, square the standard deviation and then multiply it by the number of observations n.
Sum of Squares = n ⨯ (Standard Deviation)2
The sum of squares (SS) is a measure of the spread or variability of a set of values. It can be calculated from the standard deviation (SD), which is another measure of the dispersion of data points. Here's the detailed explanation:
Understand the terms:
- The sum of Squares (SS): SS represents the sum of the squared differences between each data point and the mean of the dataset.
- Standard Deviation (SD): It is a measure of how spread out the values in a dataset are. The standard deviation is the square root of the variance, which is the average of the squared differences from the mean.
The formula for the Sum of Squares using Standard Deviation
The formula for the Sum of Squares using Standard Deviation is given by: SS = SD2 . N
Where:
SD^2 ,is the squared standard deviation.
And N ,is the number of observations in the dataset.
Standard Deviation (SD):
The standard deviation which is commonly known as the "SD" shows the extent to which the results vary from the average or mean of the data set. As it gives the information on how close the samples are spread from the average value of the dataset. When the standard deviation is smaller, the data points are very close to the mean. It means that there is less alteration in the data. A large standard deviation indicates that the data points are completely different from each other and more far-ranging; therefore, there is more variability.
Variance
Variance is one more measure that communicates the spread of data. It is expressed as the average of the squared differences from the mean. It is derived by the standard deviation with the square of its value. Variance provides the user with some idea of how dispersed the data points really are, but the variance encompasses the squares of the original data units, which makes it slightly less intuitive to directly explain.
Steps to find the sum of squares from the standard deviation:
Step 1: Calculate the Mean: Find the average of all data points.
Step 2: Calculate Deviations: Subtract the mean from each data point.
Step 3: Square Deviations: Square each deviation value.
Step 4: Find the Variance: Calculate the average of the squared deviations.
Step 5: Calculate the Standard Deviation (SD): Take the square root of the variance.
Step 6: Calculate the Sum of Squares (SS): Multiply the squared standard deviation (SD²) by the number of observations (N).
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Example Calculation: Sum of Squares Using Standard Deviation
Dataset: [3, 5, 7, 9]1. Calculate the Mean: Mean = (3 + 5 + 7 + 9) / 4 = 24 / 4 = 6 2. Calculate the Deviations from the Mean: - (3 - 6) = -3 - (5 - 6) = -1 - (7 - 6) = 1 - (9 - 6) = 3
3. Square Each Deviation
- (-3)^2 = 9 - (-1)^2 = 1 - (1)^2 = 1 - (3)^2 = 9
4. Find the Variance (Squared Standard Deviation) Variance = (9 + 1 + 1 + 9) / 4 = 20 / 4 = 5
5. Calculate the Standard Deviation (SD): SD = sqrt(5) ≈ 2.24
6. Calculate the Sum of Squares (SS): SS = SD^2 * N = 5 * 4 = 20
Practice Questions on Sum of Squares from Standard Deviation
1. A dataset contains the values [4, 8, 12, 16]. Calculate the mean, variance, standard deviation, and sum of squares.
Mean = (4 + 8 + 12 + 16) / 4 = 10 Variance = [(4-10)^2 + (8-10)^2 + (12-10)^2 + (16-10)^2] / 4 = 20 Standard Deviation = sqrt(20) ≈ 4.47 Sum of Squares = Variance * N = 20 * 4 = 80
2. You have a sample dataset [10, 15, 20, 25, 30]. Find the standard deviation and use it to calculate the sum of squares.
Mean = (10 + 15 + 20 + 25 + 30) / 5 = 20 Variance = [(10-20)^2 + (15-20)^2 + (20-20)^2 + (25-20)^2 + (30-20)^2] / 5 = 50 Standard Deviation = sqrt(50) ≈ 7.07 Sum of Squares = Variance * N = 50 * 5 = 250
3. If a dataset has a standard deviation of 3 and there are 6 observations, what is the sum of squares?
Sum of Squares = SD^2 * N = 3^2 * 6 = 9 * 6 = 54
4. A researcher is analyzing the heights of plants: [20, 22, 24, 26, 28]. Calculate the mean, variance, standard deviation, and sum of squares.
Mean = (20 + 22 + 24 + 26 + 28) / 5 = 24 Variance = [(20-24)^2 + (22-24)^2 + (24-24)^2 + (26-24)^2 + (28-24)^2] / 5 = 10 Standard Deviation = sqrt(10) ≈ 3.16Sum of Squares = Variance * N = 10 * 5 = 505.
5. In a survey, the scores collected are [50, 60, 70, 80, 90]. How would you calculate the sum of squares using standard deviation?
Mean = (50 + 60 + 70 + 80 + 90) / 5 = 70 Variance = [(50-70)^2 + (60-70)^2 + (70-70)^2 + (80-70)^2 + (90-70)^2] / 5 = 200 Standard Deviation = sqrt(200) ≈ 14.14 Sum of Squares = Variance * N = 200 * 5 = 1000
Practice Questions on Sum of Squares from Standard Deviation
Question 1: A company evaluates the performance of 6 employees using a score out of 100: [85, 90, 75, 80, 95, 88]. Calculate the mean, variance, standard deviation, and sum of squares to understand the consistency of employee performance.
Question 2: A retail store records the monthly sales in dollars for 5 months: [12000, 15000, 14000, 13000, 16000]. Find the mean, variance, standard deviation, and sum of squares to analyze the stability of the store's sales performance.
Question 3: Over a week, a city records the daily high temperatures in Celsius: [22, 25, 24, 23, 26, 22, 24]. Calculate the mean, variance, standard deviation, and sum of squares to assess the variability in temperature during the week.
Question 4: In a class of 10 students, the test scores out of 100 are: [55, 67, 74, 82, 90, 65, 76, 85, 93, 70]. Determine the mean, variance, standard deviation, and sum of squares to understand the spread of the students' performance on the test.
Conclusion
In statistics, knowing how the standard deviation works and calculating of the sum of squares is important. It enables one to obtain a perfect measure of the variability of data and hence the quality of data in a given data set. This concept is very important in areas like finance, research and quality control since decision making involves the analysis of patterns and trends of the data.