Count and Print the alphabets having ASCII value not in the range [l, r]

Last Updated : 08 Feb, 2024

Given a string str, the task is to count the number of alphabets having ASCII values, not in the range [l, r].

Examples:

Input: str = "geeksforgeeks", l = 102, r = 111
Output: Count = 7
Characters - e, s, r have ASCII values not in the range [102, 111].

Input: str = "GeEkS", l = 80, r = 111
Output: Count = 2

Approach: Start traversing the string and check if the current character has an ASCII value less than equal to r and greater than equal to l. If no then increment the count and print that element.

Below is the implementation of the above approach:

C++

// C++ implementation of the above approach
#include <bits/stdc++.h>
using namespace std;

// Function to count the number of characters
// whose ascii value not in range [l, r]
int CountCharacters(string str, int l, int r)
{
    // Initializing the count to 0
    int cnt = 0;

    // using map to print a character only once
    unordered_map<char, int> m;
    int len = str.length();
    for (int i = 0; i < len; i++) {

        // Increment the count
        // if the value is less
        if (!(l <= str[i] and str[i] <= r)) {
            cnt++;
            if (m[str[i]] != 1) {
                cout << str[i] << " ";
            m[str[i]]++;
            }
        }
    }
    // return the count
    return cnt;
}

// Driver code
int main()
{
    string str = "geeksforgeeks";
    int l = 102, r = 111;

    cout << "Characters with ASCII values"
            " not in the range [l, r] \nin the given string are: ";
    cout << "\nand their count is " << CountCharacters(str, l, r);

    return 0;
}

Java

// Java implementation of the above approach
import java.util.*;
class Solution
{
  
// Function to count the number of characters 
// whose ascii value not in range [l, r] 
static int CountCharacters(String str, int l, int r) 
{ 
    // Initializing the count to 0 
    int cnt = 0; 
  
    // using map to print a character only once 
    Map<Character, Integer> m= new HashMap<Character, Integer>(); 
    int len = str.length(); 
    for (int i = 0; i < len; i++) { 
  
        // Increment the count 
        // if the value is less 
        if (!(l <= str.charAt(i) && str.charAt(i) <= r)) { 
            cnt++; 
            if(m.get(str.charAt(i))!=null)
            if (m.get(str.charAt(i)) != 1) { 
                System.out.print(str.charAt(i) + " "); 
            m.put(str.charAt(i),m.get(str.charAt(i))==null?0:m.get(str.charAt(i))+1); 
            } 
        } 
    } 
    // return the count 
    return cnt; 
} 
  
// Driver code 
public static void main(String args[]) 
{ 
    String str = "geeksforgeeks"; 
    int l = 102, r = 111; 
  
    System.out.println( "Characters with ASCII values not in the range [l, r] \nin the given string are: "); 
     System.out.println(  "\nand their count is " + CountCharacters(str, l, r)); 
  
} 
}
//contributed by Arnab Kundu

Python3

# Python3 implementation of the
# above approach 

# Function to count the number of 
# characters whose ascii value not
# in range [l, r] 
def CountCharacters(str, l, r): 

    # Initializing the count to 0 
    cnt = 0

    # using map to print a character 
    # only once 
    m = {} 
    length = len(str) 
    for i in range(0, length):
        
        # Increment the count if the
        # value is less
        if (not(l <= ord(str[i]) and 
                     ord(str[i]) <= r)): 
            cnt += 1
            if ord(str[i]) not in m:
                m[ord(str[i])] = 0
                print(str[i], end = " ") 
            m[ord(str[i])] += 1
            
    # return the count 
    return cnt 

# Driver Code 
if __name__ == '__main__': 

    str = "geeksforgeeks"
    str = str.strip()
    l = 102
    r = 111
    print("Characters with ASCII values", end = "")
    print(" not in the range [l, r]\n",
          "in the given string are: ", end = "") 
    print("\nand their count is ", 
            CountCharacters(str, l, r)) 

# This code is contributed by
# Shubham Singh(SHUBHAMSINGH10)

// C# implementation of the above approach
using System;
using System.Collections;
using System.Collections.Generic;

class GFG
{
   
// Function to count the number of characters 
// whose ascii value not in range [l, r] 
static int CountCharacters(string str, int l, int r) 
{
  
    // Initializing the count to 0 
    int cnt = 0; 
   
    // using map to print a character only once 
    Dictionary<char, int> m = new Dictionary<char, int>(); 
    int len = str.Length; 
    for (int i = 0; i < len; i++)
    { 
   
        // Increment the count 
        // if the value is less 
        if (!(l <= str[i] && str[i] <= r))
        { 
            cnt++; 
            if(!m.ContainsKey(str[i]))
            {
                m[str[i]] = 0;
                Console.Write(str[i] + " "); 
            }
            m[str[i]]++;
        } 
    } 
  
    // return the count 
    return cnt; 
} 
   
// Driver code 
public static void Main(string []args) 
{ 
    string str = "geeksforgeeks"; 
    int l = 102, r = 111;    
    Console.Write( "Characters with ASCII values" +
                  "not in the range [l, r] \nin" + 
                  "the given string are: "); 
     Console.WriteLine( "\nand their count is " + 
                       CountCharacters(str, l, r)); 
} 
}

// This code is contributed by rutvik_56

JavaScript

<script>

// JavaScript implementation of the above approach

// Function to count the number of characters
// whose ascii value not in range [l, r]
function CountCharacters(str,l,r)
{
    // Initializing the count to 0
    let cnt = 0;
   
    // using map to print a character only once
    let m= new Map();
    let len = str.length;
    for (let i = 0; i < len; i++) {
   
        // Increment the count
        // if the value is less
        if (!(l <= str[i].charCodeAt(0) && 
        str[i].charCodeAt(0) <= r)) {
            cnt++;
            if(!m.has(str[i]))
            {
                m.set(str[i],0);
                document.write(str[i] + " ");
            }    
            m.set(str[i],m.get(str[i]+1));
        }
    }
    // return the count
    return cnt;
}

// Driver code

let str = "geeksforgeeks";
let l = 102, r = 111;

document.write( "Characters with ASCII values " +
"not in the range [l, r] <br>in the given string are: ");

document.write(  "<br>and their count is " + 
CountCharacters(str, l, r));

// This code is contributed by avanitrachhadiya2155

</script>

PHP

<?php 
// PHP implementation of the above approach

// Function to count the number of characters
// whose ascii value not in range [l, r]
function CountCharacters($str, $l, $r)
{
    // Initializing the count to 0
    $cnt = 0;

    // using map to print a character
    // only once
    $m = array_fill(0, 256, NULL);
    $len = strlen($str);
    for ($i = 0; $i < $len; $i++) 
    {

        // Increment the count
        // if the value is less
        if (!($l <= ord($str[$i]) and 
                    ord($str[$i]) <= $r)) 
        {
            $cnt++;
            if (isset($m[ord($str[$i])]) != 1)
            {
                echo $str[$i] . " ";
                $m[ord($str[$i])]++;
            }
        }
    }
    // return the count
    return $cnt;
}

// Driver code
$str = "geeksforgeeks";
$l = 102;
$r = 111;
echo "Characters with ASCII values not in the " . 
      "range [l, r] \nin the given string are: ";
echo "\nand their count is " . 
       CountCharacters($str, $l, $r);

// This code is contributed 
// by ChitraNayal
?>

Output

Characters with ASCII values not in the range [l, r] 
in the given string are: e s r 
and their count is 7

Complexity Analysis:

Time Complexity: O(n) where n is the length of string.
Space Complexity: O(n) for unordered_map

Print each word in a sentence with their corresponding average of ASCII values

VishalBachchas

Improve

Article Tags :

Practice Tags :

Strings

Count and Print the alphabets having ASCII value not in the range [l, r]

Similar Reads

Program to Print ASCII Conversion

Program for Binary to ASCII Conversion

Problem Related to ASCCI

Thank You!

What kind of Experience do you want to share?