Check if a number is Primorial Prime or not Last Updated : 25 Aug, 2022 Comments Improve Suggest changes Like Article Like Report Given a positive number N, the task is to check if N is a primorial prime number or not. Print 'YES' if N is a primorial prime number otherwise print 'NO.Primorial Prime: In Mathematics, A Primorial prime is a prime number of the form pn# + 1 or pn# - 1 , where pn# is the primorial of pn i.e the product of first n prime numbers.Examples: Input : N = 5 Output : YES 5 is Primorial prime of the form pn - 1 for n=2, Primorial is 2*3 = 6 and 6-1 =5. Input : N = 31 Output : YES 31 is Primorial prime of the form pn + 1 for n=3, Primorial is 2*3*5 = 30 and 30+1 = 31. The First few Primorial primes are: 2, 3, 5, 7, 29, 31, 211, 2309, 2311, 30029 Prerequisite: PrimorialSieve of Eratosthenes Approach: Generate all prime number in the range using Sieve of Eratosthenes.Check if n is prime or not, If n is not prime Then print NoElse, starting from first prime (i.e 2 ) start multiplying next prime number and keep checking if product + 1 = n or product - 1 = n or notIf either product+1=n or product-1=n, then n is a Primorial Prime Otherwise not. Below is the implementation of above approach: C++ // CPP program to check Primorial Prime #include <bits/stdc++.h> using namespace std; #define MAX 10000 vector<int> arr; bool prime[MAX]; // Function to generate prime numbers void SieveOfEratosthenes() { // Create a boolean array "prime[0..n]" and initialize // make all entries of boolean array 'prime' // as true. A value in prime[i] will // finally be false if i is Not a prime, else true. memset(prime, true, sizeof(prime)); for (int p = 2; p * p < MAX; p++) { // If prime[p] is not changed, then it is a prime if (prime[p] == true) { // Update all multiples of p for (int i = p * 2; i < MAX; i += p) prime[i] = false; } } // store all prime numbers // to vector 'arr' for (int p = 2; p < MAX; p++) if (prime[p]) arr.push_back(p); } // Function to check the number for Primorial prime bool isPrimorialPrime(long n) { // If n is not prime Number // return false if (!prime[n]) return false; long long product = 1; int i = 0; while (product < n) { // Multiply next prime number // and check if product + 1 = n or Product-1 =n // holds or not product = product * arr[i]; if (product + 1 == n || product - 1 == n) return true; i++; } return false; } // Driver code int main() { SieveOfEratosthenes(); long n = 31; // Check if n is Primorial Prime if (isPrimorialPrime(n)) cout << "YES\n"; else cout << "NO\n"; return 0; } Java // Java program to check Primorial prime import java.util.*; class GFG { static final int MAX = 1000000; static Vector<Integer> arr = new Vector<Integer>(); static boolean[] prime = new boolean[MAX]; // Function to get the prime numbers static void SieveOfEratosthenes() { // make all entries of boolean array 'prime' // as true. A value in prime[i] will // finally be false if i is Not a prime, else true. for (int i = 0; i < MAX; i++) prime[i] = true; for (int p = 2; p * p < MAX; p++) { // If prime[p] is not changed, then it is a prime if (prime[p] == true) { // Update all multiples of p for (int i = p * 2; i < MAX; i += p) prime[i] = false; } } // store all prime numbers // to vector 'arr' for (int p = 2; p < MAX; p++) if (prime[p]) arr.add(p); } // Function to check the number for Primorial prime static boolean isPrimorialPrime(int n) { // If n is not prime // Then return false if (!prime[n]) return false; long product = 1; int i = 0; while (product < n) { // Multiply next prime number // and check if product + 1 = n or product -1=n // holds or not product = product * arr.get(i); if (product + 1 == n || product - 1 == n) return true; i++; } return false; } // Driver Code public static void main(String[] args) { SieveOfEratosthenes(); int n = 31; if (isPrimorialPrime(n)) System.out.println("YES"); else System.out.println("NO"); } } Python 3 # Python3 Program to check Primorial Prime # from math lib import sqrt method from math import sqrt MAX = 100000 # Create a boolean array "prime[0..n]" # and initialize make all entries of # boolean array 'prime' as true. # A value in prime[i] will finally be # false if i is Not a prime, else true. prime = [True] * MAX arr = [] # Utility function to generate # prime numbers def SieveOfEratosthenes() : for p in range(2, int(sqrt(MAX)) + 1) : # If prime[p] is not changed, # then it is a prime if prime[p] == True : # Update all multiples of p for i in range(p * 2 , MAX, p) : prime[i] = False # store all prime numbers # to list 'arr' for p in range(2, MAX) : if prime[p] : arr.append(p) # Function to check the number # for Primorial prime def isPrimorialPrime(n) : # If n is not prime Number # return false if not prime[n] : return False product, i = 1, 0 # Multiply next prime number # and check if product + 1 = n # or Product-1 = n holds or not while product < n : product *= arr[i] if product + 1 == n or product - 1 == n : return True i += 1 return False # Driver code if __name__ == "__main__" : SieveOfEratosthenes() n = 31 # Check if n is Primorial Prime if (isPrimorialPrime(n)) : print("YES") else : print("NO") # This code is contributed by ANKITRAI1 C# // c# program to check Primorial prime using System; using System.Collections.Generic; public class GFG { public const int MAX = 1000000; public static List<int> arr = new List<int>(); public static bool[] prime = new bool[MAX]; // Function to get the prime numbers public static void SieveOfEratosthenes() { // make all entries of boolean array 'prime' // as true. A value in prime[i] will // finally be false if i is Not a prime, else true. for (int i = 0; i < MAX; i++) { prime[i] = true; } for (int p = 2; p * p < MAX; p++) { // If prime[p] is not changed, then it is a prime if (prime[p] == true) { // Update all multiples of p for (int i = p * 2; i < MAX; i += p) { prime[i] = false; } } } // store all prime numbers // to vector 'arr' for (int p = 2; p < MAX; p++) { if (prime[p]) { arr.Add(p); } } } // Function to check the number for Primorial prime public static bool isPrimorialPrime(int n) { // If n is not prime // Then return false if (!prime[n]) { return false; } long product = 1; int i = 0; while (product < n) { // Multiply next prime number // and check if product + 1 = n or product -1=n // holds or not product = product * arr[i]; if (product + 1 == n || product - 1 == n) { return true; } i++; } return false; } // Driver Code public static void Main(string[] args) { SieveOfEratosthenes(); int n = 31; if (isPrimorialPrime(n)) { Console.WriteLine("YES"); } else { Console.WriteLine("NO"); } } } // This code is contributed by Shrikant13 PHP <?php // PHP Program to check Primorial Prime $MAX = 100000; // Create a boolean array "prime[0..n]" // and initialize make all entries of // boolean array 'prime' as true. // A value in prime[i] will finally be // false if i is Not a prime, else true. $prime = array_fill(0, $MAX, true); $arr = array(); // Utility function to generate // prime numbers function SieveOfEratosthenes() { global $MAX, $prime, $arr; for($p = 2; $p <= (int)(sqrt($MAX)); $p++) { // If prime[p] is not changed, // then it is a prime if ($prime[$p] == true) // Update all multiples of p for ($i = $p * 2; $i < $MAX; $i += $p) $prime[$i] = false; } // store all prime numbers // to list 'arr' for ($p = 2; $p < $MAX; $p++) if ($prime[$p]) array_push($arr, $p); } // Function to check the number // for Primorial prime function isPrimorialPrime($n) { global $MAX, $prime, $arr; // If n is not prime Number // return false if(!$prime[$n]) return false; $product = 1; $i = 0; // Multiply next prime number // and check if product + 1 = n // or Product-1 = n holds or not while ($product < $n) { $product *= $arr[$i]; if ($product + 1 == $n || $product - 1 == $n ) return true; $i += 1; } return false; } // Driver code SieveOfEratosthenes(); $n = 31; // Check if n is Primorial Prime if (isPrimorialPrime($n)) print("YES"); else print("NO"); // This code is contributed by mits JavaScript <script> // Javascript program to check Primorial Prime var MAX = 10000; var arr = []; var prime = Array(MAX).fill(true); // Function to generate prime numbers function SieveOfEratosthenes() { // Create a boolean array "prime[0..n]" and initialize // make all entries of boolean array 'prime' // as true. A value in prime[i] will // finally be false if i is Not a prime, else true. for (var p = 2; p * p < MAX; p++) { // If prime[p] is not changed, then it is a prime if (prime[p] == true) { // Update all multiples of p for (var i = p * 2; i < MAX; i += p) prime[i] = false; } } // store all prime numbers // to vector 'arr' for (var p = 2; p < MAX; p++) if (prime[p]) arr.push(p); } // Function to check the number for Primorial prime function isPrimorialPrime(n) { // If n is not prime Number // return false if (!prime[n]) return false; var product = 1; var i = 0; while (product < n) { // Multiply next prime number // and check if product + 1 = n or Product-1 =n // holds or not product = product * arr[i]; if (product + 1 == n || product - 1 == n) return true; i++; } return false; } // Driver code SieveOfEratosthenes(); var n = 31; // Check if n is Primorial Prime if (isPrimorialPrime(n)) document.write( "YES"); else document.write("NO"); </script> Output: YES Time Complexity: O(n + MAX3/2) Auxiliary Space: O(MAX) Comment More infoAdvertise with us Next Article Sum of all Primes in a given range using Sieve of Eratosthenes I ihritik Follow Improve Article Tags : Mathematical DSA series sieve Prime Number number-theory +2 More Practice Tags : Mathematicalnumber-theoryPrime Numberseriessieve +1 More Similar Reads Check for Prime Number Given a number n, check whether it is a prime number or not.Note: A prime number is a number greater than 1 that has no positive divisors other than 1 and itself.Input: n = 7Output: trueExplanation: 7 is a prime number because it is greater than 1 and has no divisors other than 1 and itself.Input: n 11 min read Primality Test AlgorithmsIntroduction to Primality Test and School MethodGiven a positive integer, check if the number is prime or not. 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