D3.js | d3.timeMondays() Function Last Updated : 23 Jul, 2019 Comments Improve Suggest changes Like Article Like Report The d3.timeMondays() function in D3.js is used to return all the dates based on Monday in the given range of start and end date. Syntax: d3.timeMondays( start, end, step ); Parameters: This function accept three parameters as mentioned above and described below: Start: This parameter holds the given start date. end: This parameter holds the given end date. step: It is the optional parameter and the value used to skip dates. Return Value: This function returns all the dates based on Monday. Below programs illustrate the d3.timeMondays() function in D3.js: Example 1: javascript <!DOCTYPE html> <html> <head> <title> D3.js | d3.timeMondays() Function </title> <script src = "https://d3js.org/d3.v4.min.js"> </script> </head> <body> <script> // Initialising start and end date var start = new Date(2015, 07, 01); var end = new Date(2015, 07, 30); // Calling the timeMondays() function // without step value var a = d3.timeMondays(start, end); // Getting the Monday dates console.log(a); </script> </body> </html> Output: ["2015-08-02T18:30:00.000Z", "2015-08-09T18:30:00.000Z", "2015-08-16T18:30:00.000Z", "2015-08-23T18:30:00.000Z"] Example 2: javascript <!DOCTYPE html> <html> <head> <title> D3.js | d3.timeMondays() Function </title> <script src = "https://d3js.org/d3.v4.min.js"> </script> </head> <body> <script> // Initialising start and end date var start = new Date(2015, 07, 01); var end = new Date(2015, 07, 30); // Calling the timeMondays() function // with step value var a = d3.timeMondays(start, end, 2); // Getting the Monday dates console.log(a); </script> </body> </html> Output: ["2015-08-02T18:30:00.000Z", "2015-08-16T18:30:00.000Z"] Reference: https://devdocs.io/d3~5/d3-time#timeMondays Comment More infoAdvertise with us Next Article D3.js | d3.timeMondays() Function K Kanchan_Ray Follow Improve Article Tags : JavaScript Web Technologies D3.js Similar Reads D3.js | d3.timeMonday Function The d3.timeMonday function in D3.js is used to return all the dates based on Monday in the given range of start and end date. Syntax: d3.timeMonday.range( start, end, step ); Parameters: This function accept three parameters which are given below: Start: This parameter holds the given start date. en 2 min read D3.js | d3.timeDays() Function The d3.timeDays() function in D3.js is used to return all the dates in between two given dates. Syntax: d3.timeDays(Start, End, step); Parameters: This function accept three parameters which are given below: Start: This is the given start date. End: This is the given end date. step: This parameter i 1 min read D3.js | d3.timeDay() Function The d3.timeDay() function in D3.js is used to return date in "YYYY-MM-DD" format. Syntax: d3.timeDay(Date); Parameters: This function accepts a parameter "Date". Return Value: This function returns the given date in a specific format. Below programs illustrate the d3.timeDay() function in D3.js: Exa 1 min read D3.js | d3.timeSundays() Function The d3.timeSundays() function in D3.js is used to return all the dates based on Sunday in the given range of start and end date. Syntax: d3.timeSundays(start, end, step); Parameters: This function accept three parameters which are given below: Start: This parameter holds the given start date. end: T 2 min read D3.js | d3.utcMondays() Function The d3.utcMondays() function in D3.js is used to return all the dates based on Monday in the given range of start and end date in Coordinated Universal Time (UTC). Syntax: d3.utcMondays( start, end, step ); Parameters: This function accept three parameters which are given below: Start: This paramete 2 min read Like