Pattern Searching using C++ library Last Updated : 03 May, 2023 Summarize Comments Improve Suggest changes Share Like Article Like Report Given a text txt[0..n-1] and a pattern pat[0..m-1], write a function that prints all occurrences of pat[] in txt[]. You may assume that n > m.Examples: Input : txt[] = "geeks for geeks" pat[] = "geeks" Output : Pattern found at index 0 Pattern found at index 10 Input : txt[] = "aaaa" pat[] = "aa" Output : Pattern found at index 0 Pattern found at index 1 Pattern found at index 2 The idea is to use find() in C++ string class. CPP // CPP program to print all occurrences of a pattern // in a text #include <bits/stdc++.h> using namespace std; void printOccurrences(string txt, string pat) { int found = txt.find(pat); while (found != string::npos) { cout << "Pattern found at index " << found << endl; found = txt.find(pat, found + 1); } } int main() { string txt = "aaaa", pat = "aa"; printOccurrences(txt, pat); return 0; } Output: Pattern found at index 0 Pattern found at index 1 Pattern found at index 2 Time and Space Complexity: The given program uses the string find() function to find all occurrences of a pattern in a text. The find() function returns the index of the first occurrence of the pattern in the text, or string::npos if the pattern is not found. The program repeatedly calls the find() function with an updated starting index until all occurrences of the pattern are found. The time complexity of the program is determined by the time complexity of the find() function, which is O(NM), where N is the length of the text and M is the length of the pattern. In the worst case, the program may need to call the find() function for every substring of length M in the text, resulting in a time complexity of O(NM^2). The space complexity of the program is determined by the space used to store the text and pattern strings. In addition, the program uses some local variables for indexing and temporary storage, but their space usage is negligible compared to the input strings. Therefore, the space complexity of the program is O(N+M), where N and M are the lengths of the text and pattern strings, respectively. Overall, the program is efficient for finding all occurrences of a pattern in a small to medium-sized text. However, for large texts, the time complexity of the program may become a bottleneck, and more advanced string matching algorithms, such as the Knuth-Morris-Pratt algorithm or the Boyer-Moore algorithm, may be more appropriate. Comment More infoAdvertise with us Next Article Pattern Searching using C++ library R rupayan_nitdgp Follow Improve Article Tags : C++ Practice Tags : CPP Similar Reads What is Pattern Searching ? Pattern searching in Data Structures and Algorithms (DSA) is a fundamental concept that involves searching for a specific pattern or sequence of elements within a given data structure. This technique is commonly used in string matching algorithms to find occurrences of a particular pattern within a 5 min read Introduction to Pattern Searching - Data Structure and Algorithm Tutorial Pattern searching is an algorithm that involves searching for patterns such as strings, words, images, etc. We use certain algorithms to do the search process. The complexity of pattern searching varies from algorithm to algorithm. They are very useful when performing a search in a database. The Pat 15+ min read Naive algorithm for Pattern Searching Given text string with length n and a pattern with length m, the task is to prints all occurrences of pattern in text. Note: You may assume that n > m. Examples:Â Input: Â text = "THIS IS A TEST TEXT", pattern = "TEST"Output: Pattern found at index 10 Input: Â text = Â "AABAACAADAABAABA", pattern = 6 min read Rabin-Karp Algorithm for Pattern Searching Given two strings text and pattern string, your task is to find all starting positions where the pattern appears as a substring within the text. The strings will only contain lowercase English alphabets.While reporting the results, use 1-based indexing (i.e., the first character of the text is at po 12 min read KMP Algorithm for Pattern Searching Given two strings txt and pat, the task is to return all indices of occurrences of pat within txt. Examples:Input: txt = "abcab", pat = "ab"Output: [0, 3]Explanation: The string "ab" occurs twice in txt, first occurrence starts from index 0 and second from index 3.Input: txt= "aabaacaadaabaaba", pat 14 min read Z algorithm (Linear time pattern searching Algorithm) This algorithm efficiently locates all instances of a specific pattern within a text in linear time. If the length of the text is "n" and the length of the pattern is "m," then the total time taken is O(m + n), with a linear auxiliary space. It is worth noting that the time and auxiliary space of th 13 min read Finite Automata algorithm for Pattern Searching Given a text txt[0..n-1] and a pattern pat[0..m-1], write a function search(char pat[], char txt[]) that prints all occurrences of pat[] in txt[]. You may assume that n > m.Examples: Input: txt[] = "THIS IS A TEST TEXT" pat[] = "TEST" Output: Pattern found at index 10 Input: txt[] = "AABAACAADAAB 13 min read Boyer Moore Algorithm for Pattern Searching Pattern searching is an important problem in computer science. When we do search for a string in a notepad/word file, browser, or database, pattern searching algorithms are used to show the search results. A typical problem statement would be-Â " Given a text txt[0..n-1] and a pattern pat[0..m-1] whe 15+ min read Aho-Corasick Algorithm for Pattern Searching Given an input text and an array of k words, arr[], find all occurrences of all words in the input text. Let n be the length of text and m be the total number of characters in all words, i.e. m = length(arr[0]) + length(arr[1]) + ... + length(arr[k-1]). Here k is total numbers of input words. Exampl 15+ min read ÂÂkasaiâs Algorithm for Construction of LCP array from Suffix Array Background Suffix Array : A suffix array is a sorted array of all suffixes of a given string. Let the given string be "banana". 0 banana 5 a1 anana Sort the Suffixes 3 ana2 nana ----------------> 1 anana 3 ana alphabetically 0 banana 4 na 4 na 5 a 2 nanaThe suffix array for "banana" :suffix[] = { 15+ min read Like