Convert given string to a valid mobile number
Last Updated :
20 Aug, 2021
Given a string M consisting of letters, digits and symbols, the task is to convert the string to a valid mobile number by removing all characters except the digits in the following format:
- Form a substring of 3 digits while the length of the remaining string is greater than 3.
- Enclose each substring with brackets "()" and separate them with "-".
If a valid mobile number cannot be obtained, i.e. if the string does not consist of 10 digits, then print -1. Otherwise, print the string obtained.
Examples:
Input: M = "91 234rt5%34*0 3"
Output: "(912)-(345)-(340)-(3)"
Explanation: After removing all extra characters, M = "9123453403". Therefore, the final string obtained is "(912)-(345)-(340)-(3)".
Input: M="9 9 ry7%64 9 7"
Output: "Invalid"
Explanation: After removing extra characters M="9976497". Since the length of the string is not equal to 10, the required output is -1.
Approach: Follow the below steps to solve the problem:
- Initialize a string, say S and append all digits of M in S in the given order.
- Now, if the length of S is not 10, print "Invalid", and end the program.
- Otherwise, if the length of the string S is 10, make a group of 3 characters and enclose it within the brackets "()" and make separate it with "-".
- Print final string as S.
Below is the solution for the above problem.
C++
// C++ program for the above approach
#include <bits/stdc++.h>
using namespace std;
// Function to print the valid
// and formatted phone number
void Validate(string M)
{
// Length of given string
int len = M.size();
// Store digits in temp
string temp = "";
// Iterate given M
for (int i = 0; i < len; i++) {
// If any digit, append it to temp
if (isdigit(M[i]))
temp += M[i];
}
// Find new length of string
int nwlen = temp.size();
// If length is not equal to 10
if (nwlen != 10) {
cout << "Invalid\n";
return;
}
// Store final result
string res = "";
// Make groups of 3 digits and
// enclose them within () and
// separate them with "-"
// 0 to 2 index 1st group
string x = temp.substr(0, 3);
res += "(" + x + ")-";
// 3 to 5 index 2nd group
x = temp.substr(3, 3);
res += "(" + x + ")-";
// 6 to 8 index 3rd group
x = temp.substr(6, 3);
res += "(" + x + ")-";
// 9 to 9 index last group
x = temp.substr(9, 1);
res += "(" + x + ")";
// Print final result
cout << res << "\n";
}
// Driver Code
int main()
{
// Given string
string M = "91 234rt5%34*0 3";
// Function Call
Validate(M);
}
// contributed by ajaykr00kj
// Java program for the above approach
import java.util.*;
class GFG
{
// Function to print the valid
// and formatted phone number
static void Validate(String M)
{
// Length of given String
int len = M.length();
// Store digits in temp
String temp = "";
// Iterate given M
for (int i = 0; i < len; i++)
{
// If any digit, append it to temp
if (Character.isDigit(M.charAt(i)))
temp += M.charAt(i);
}
// Find new length of String
int nwlen = temp.length();
// If length is not equal to 10
if (nwlen != 10)
{
System.out.print("Invalid\n");
return;
}
// Store final result
String res = "";
// Make groups of 3 digits and
// enclose them within () and
// separate them with "-"
// 0 to 2 index 1st group
String x = temp.substring(0, 3);
res += "(" + x + ")-";
// 3 to 5 index 2nd group
x = temp.substring(3, 6);
res += "(" + x + ")-";
// 6 to 8 index 3rd group
x = temp.substring(6, 9);
res += "(" + x + ")-";
// 9 to 9 index last group
x = temp.substring(9, 10);
res += "(" + x + ")";
// Print final result
System.out.print(res+ "\n");
}
// Driver Code
public static void main(String[] args)
{
// Given String
String M = "91 234rt5%34*0 3";
// Function Call
Validate(M);
}
}
// This code is contributed by shikhasingrajput
# Python3 program for the above approach
# Function to print valid
# and formatted phone number
def Validate(M):
# Length of given
lenn = len(M)
# Store digits in temp
temp = ""
# Iterate given M
for i in range(lenn):
# If any digit:append it to temp
if (M[i].isdigit()):
temp += M[i]
# Find new length of
nwlenn = len(temp)
# If length is not equal to 10
if (nwlenn != 10):
print ("Invalid")
return
# Store final result
res = ""
# Make groups of 3 digits and
# enclose them within () and
# separate them with "-"
# 0 to 2 index 1st group
x = temp[0:3]
res += "(" + x + ")-"
# 3 to 5 index 2nd group
x = temp[3 : 3 + 3]
res += "(" + x + ")-"
# 6 to 8 index 3rd group
x = temp[6 : 3 + 6]
res += "(" + x + ")-"
# 9 to 9 index last group
x = temp[9 : 1 + 9]
res += "(" + x + ")"
# Print final result
print(res)
# Driver Code
if __name__ == '__main__':
# Given
M = "91 234rt5%34*0 3"
# Function Call
Validate(M)
# This code is contributed by mohit kumar 29
// C# program for the above approach
using System;
class GFG
{
// Function to print the valid
// and formatted phone number
static void Validate(string M)
{
// Length of given String
int len = M.Length;
// Store digits in temp
string temp = "";
// Iterate given M
for (int i = 0; i < len; i++)
{
// If any digit, append it to temp
if (Char.IsDigit(M[i]))
temp += M[i];
}
// Find new length of String
int nwlen = temp.Length;
// If length is not equal to 10
if (nwlen != 10)
{
Console.Write("Invalid\n");
return;
}
// Store final result
string res = "";
// Make groups of 3 digits and
// enclose them within () and
// separate them with "-"
// 0 to 2 index 1st group
string x = temp.Substring(0, 3);
res += "(" + x + ")-";
// 3 to 5 index 2nd group
x = temp.Substring(3, 3);
res += "(" + x + ")-";
// 6 to 8 index 3rd group
x = temp.Substring(6, 3);
res += "(" + x + ")-";
// 9 to 9 index last group
x = temp.Substring(9, 1);
res += "(" + x + ")";
// Print final result
Console.WriteLine(res);
}
// Driver Code
public static void Main(string[] args)
{
// Given String
string M = "91 234rt5%34*0 3";
// Function Call
Validate(M);
}
}
// This code is contributed by AnkThon
<script>
// JavaScript program for the above approach
// Function to print the valid
// and formatted phone number
function Validate(M)
{
// Length of given String
let len = M.length;
// Store digits in temp
let temp = "";
// Iterate given M
for (let i = 0; i < len; i++)
{
// If any digit, append it to temp
if (! isNaN( parseInt(M[i]) ))
temp += M[i];
}
// Find new length of String
let nwlen = temp.length;
// If length is not equal to 10
if (nwlen != 10)
{
document.write("Invalid<br>");
return;
}
// Store final result
let res = "";
// Make groups of 3 digits and
// enclose them within () and
// separate them with "-"
// 0 to 2 index 1st group
let x = temp.substring(0, 3);
res += "(" + x + ")-";
// 3 to 5 index 2nd group
x = temp.substring(3, 6);
res += "(" + x + ")-";
// 6 to 8 index 3rd group
x = temp.substring(6, 9);
res += "(" + x + ")-";
// 9 to 9 index last group
x = temp.substring(9, 10);
res += "(" + x + ")";
// Print final result
document.write(res+ "<br>");
}
// Driver Code
// Given String
let M = "91 234rt5%34*0 3";
// Function Call
Validate(M);
// This code is contributed by patel2127
</script>
Output: (912)-(345)-(340)-(3)
Time Complexity: O(|M|+|S|)
Auxiliary Space: O(|M|+|S|)
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