Check whether the number can be made perfect square after adding K

Last Updated : 16 Oct, 2022

Given two numbers N and K, the task is to check whether the given number N can be made a perfect square after adding K to it.
Examples:

Input: N = 7, K = 2
Output: Yes
Explanation:
7 + 2 = 9 which is a perfect square.

Input: N = 5, K = 3
Output: No
Explanation:
5 + 3 = 8 which is not a perfect square.

Approach: The idea is to compute the value of N + K and check if it is a perfect square or not. In order to check if a number is a perfect square or not, refer to this article.

Below is the implementation of the above approach:

C++

// C++ program to check whether the number
// can be made perfect square after adding K

#include <bits/stdc++.h>
using namespace std;

// Function to check whether the number
// can be made perfect square after adding K
void isPerfectSquare(long long int x)
{

    // Computing the square root of
    // the number
    long double sr = round(sqrt(x));

    // Print Yes if the number
    // is a perfect square
    if (sr * sr == x)
        cout << "Yes";
    else
        cout << "No";
}

// Driver code
int main()
{
    int n = 7, k = 2;
    isPerfectSquare(n + k);

    return 0;
}

Java

// Java program to check whether the number
// can be made perfect square after adding K
import java.util.*;

class GFG
{
    
    // Function to check whether the number
    // can be made perfect square after adding K
    static void isPerfectSquare(int x)
    {
    
        // Computing the square root of
        // the number
        int sr = (int)Math.sqrt(x);
    
        // Print Yes if the number
        // is a perfect square
        if (sr * sr == x)
            System.out.println("Yes");
        else
            System.out.println("No");
    }
    
    // Driver code
    public static void main(String args[])
    {
        int n = 7, k = 2;
        isPerfectSquare(n + k);
    
    }
}

// This code is contributed by Yash_R

Python3

# Python3 program to check whether the number 
# can be made perfect square after adding K 
from math import sqrt

# Function to check whether the number 
# can be made perfect square after adding K 
def isPerfectSquare(x) : 

    # Computing the square root of 
    # the number 
    sr = int(sqrt(x)); 

    # Print Yes if the number 
    # is a perfect square 
    if (sr * sr == x) :
        print("Yes"); 
    else :
        print("No"); 

# Driver code 
if __name__ == "__main__" : 

    n = 7; k = 2; 
    isPerfectSquare(n + k); 

# This code is contributed by Yash_R

// C# program to check whether the number
// can be made perfect square after adding K
using System;

class GFG
{
    
    // Function to check whether the number
    // can be made perfect square after adding K
    static void isPerfectSquare(int x)
    {
    
        // Computing the square root of
        // the number
        int sr = (int)Math.Sqrt(x);
    
        // Print Yes if the number
        // is a perfect square
        if (sr * sr == x)
            Console.WriteLine("Yes");
        else
            Console.WriteLine("No");
    }
    
    // Driver code
    public static void Main(String []args)
    {
        int n = 7;
        int k = 2;
        isPerfectSquare(n + k);    
    }
}

// This code is contributed by Yash_R

JavaScript

<script>

// Javascript program to check whether the number
// can be made perfect square after adding K

// Function to check whether the number
// can be made perfect square after adding K
function isPerfectSquare(x)
{

    // Computing the square root of
    // the number
    var sr = Math.round(Math.sqrt(x));

    // Print Yes if the number
    // is a perfect square
    if (sr * sr == x)
        document.write("Yes");
    else
        document.write("No");
}

// Driver code
var n = 7, k = 2;
isPerfectSquare(n + k);

</script>