C Program For Deleting A Linked List Node At A Given Position
Last Updated :
16 Jun, 2022
Given a singly linked list and a position, delete a linked list node at the given position.
Example:
Input: position = 1, Linked List = 8->2->3->1->7
Output: Linked List = 8->3->1->7
Input: position = 0, Linked List = 8->2->3->1->7
Output: Linked List = 2->3->1->7
If the node to be deleted is the root, simply delete it. To delete a middle node, we must have a pointer to the node previous to the node to be deleted. So if positions are not zero, we run a loop position-1 times and get a pointer to the previous node.
Below is the implementation of the above idea.
C
// A complete working C program to delete a node in a linked list
// at a given position
#include <stdio.h>
#include <stdlib.h>
// A linked list node
struct Node
{
int data;
struct Node *next;
};
/* Given a reference (pointer to pointer) to the head of a list
and an int inserts a new node on the front of the list. */
void push(struct Node** head_ref, int new_data)
{
struct Node* new_node = (struct Node*) malloc(sizeof(struct Node));
new_node->data = new_data;
new_node->next = (*head_ref);
(*head_ref) = new_node;
}
/* Given a reference (pointer to pointer) to the head of a list
and a position, deletes the node at the given position */
void deleteNode(struct Node **head_ref, int position)
{
// If linked list is empty
if (*head_ref == NULL)
return;
// Store head node
struct Node* temp = *head_ref;
// If head needs to be removed
if (position == 0)
{
*head_ref = temp->next; // Change head
free(temp); // free old head
return;
}
// Find previous node of the node to be deleted
for (int i=0; temp!=NULL && i<position-1; i++)
temp = temp->next;
// If position is more than number of nodes
if (temp == NULL || temp->next == NULL)
return;
// Node temp->next is the node to be deleted
// Store pointer to the next of node to be deleted
struct Node *next = temp->next->next;
// Unlink the node from linked list
free(temp->next); // Free memory
temp->next = next; // Unlink the deleted node from list
}
// This function prints contents of linked list starting from
// the given node
void printList(struct Node *node)
{
while (node != NULL)
{
printf(" %d ", node->data);
node = node->next;
}
}
/* Driver program to test above functions*/
int main()
{
/* Start with the empty list */
struct Node* head = NULL;
push(&head, 7);
push(&head, 1);
push(&head, 3);
push(&head, 2);
push(&head, 8);
puts("Created Linked List: ");
printList(head);
deleteNode(&head, 4);
puts("
Linked List after Deletion at position 4: ");
printList(head);
return 0;
}
Output:
Created Linked List:
8 2 3 1 7
Linked List after Deletion at position 4:
8 2 3 1
Time Complexity: O(n), where n represents the length of the given linked list.
Auxiliary Space: O(1), no extra space is required, so it is a constant.
Please refer complete article on Delete a Linked List node at a given position for more details!
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