Binary Search in Java

Last Updated : 11 Apr, 2025

Binary search is a highly efficient searching algorithm used when the input is sorted. It works by repeatedly dividing the search range in half, reducing the number of comparisons needed compared to a linear search. Here, we are focusing on finding the middle element that acts as a reference frame to determine whether to go left or right to it as the elements are already sorted This makes it ideal for large datasets, where it achieves a time complexity of O(log N) far faster than O(N) for sequential search.

Example Input/Output:

Input: arr = { 3, 5, 7, 8, 10, 12, 15}, target = 7
Output: 2
Input: arr = { 1, 2, 3, 4, 5, 6, 7, 8} target = 10
Output: -1 ( Because the target is not present in the array)

Key Points:

Sorted Array: Binary search only works on sorted arrays or lists. Unsorted inputs give undefined results.
Duplicate Values: If duplicates exist, the returned index depends on the implementation (e.g., it may return the first or any occurrence).
Efficient: Binary search is efficient for a large dataset if the given input is sorted. Always refer to binary search over sequential search.

Binary Search Algorithm in Java

Below is the Algorithm designed for Binary Search:

Start
Take input array and Target
Initialise start = 0 and end = (array size -1)
Intialise mid variable
mid = (start+end)/2
if array[ mid ] == target then return mid
if array[ mid ] < target then start = mid+1
if array[ mid ] > target then end = mid-1
if start<=end then goto step 5
return -1 as target not found
Exit

Now you must be thinking what if the input is not sorted then the results are undefined.

Note: If there are duplicates, there is no guarantee which one will be found.

Importance of Binary Search

It eliminates half the remaining elements in each step, making it optimal for large datasets.
It is used in databases, search algorithms, and performance critical applications.

Methods for Java Binary Search

There are three methods in Java to implement Binary Search in Java are mentioned below:

Iterative Method
Recursive Method
Inbuild Method

1. Iterative Method for Binary Search in Java

Example: Binary Search program using iterative method.

Java

// Java implementation of iterative Binary Search
class Geeks
{
   static int binarySearch(int a[], int l, int r, int x)
    {
        while (l <= r) {
            int m = (l + r) / 2;

            // Index of Element Returned
            if (a[m] == x) {
                return m;

            // If element is smaller than mid, then
            // it can only be present in left subarray
            // so we decrease our r pointer to mid - 1 
            } else if (a[m] > x) {
                r = m - 1;

            // Else the element can only be present
            // in right subarray
            // so we increase our l pointer to mid + 1
            } else {
              l = m + 1;
            }  
        }

        // No Element Found
        return -1;
    }

    public static void main(String args[])
    {

        int a[] = { 2, 3, 4, 10, 40 };
        int n = a.length;
        int x = 10;
      
        int res = binarySearch(a, 0, n - 1, x);

         System.out.println("Element to be searched is : "+ x); 

        if (res == -1)
            System.out.println("Element is not present in array");
        else
            System.out.println("Element is present at index: " + res);
    }
}

Output

Element to be searched is : 10
Element is present at index: 3

Tip: Geeks you must be wondering out whether there is any function like lower_bound() or upper_bound() just likely found in C++ STL. so the straight answer is that there was no function only till Java 9, later onwards they were added.

2. Recursive Method for Binary Search

Example: Binary Search program using recursion.

Java

// Java implementation of
// recursive Binary Search
public class Geeks
{
    static int binarySearch(int a[], int l, int r, int x)
    {

      	if (r >= l) {
            int m = l + (r - l) / 2;

            // Returned Index of the Element
            if (a[m] == x)
                return m;

            // If element is smaller than mid, then
            // it can only be present in left subarray
            if (a[m] > x)
                return binarySearch(a, l, m - 1, x);

            // Else the element can only be present
            // in right subarray
            return binarySearch(a, m + 1, r, x);
        }

        // No Element Found
        return -1;
    }

    // main function
    public static void main(String args[])
    {
        int a[] = { 2, 3, 4, 10, 40 };
        int n = a.length;
        int x = 10;
      
        int res = binarySearch(a, 0, n - 1, x);

       System.out.println("Element to be searched is : "+ x); 

        if (res == -1)
            System.out.println(
                "Element is not present in array");
        else
            System.out.println("Element is present at index: " + res);
    }
}

Output

Element to be searched is : 10
Element is present at index: 3

Complexity of the above method

Time Complexity: O(log N)
Space Complexity: O(1), If the recursive call stack is considered then the auxiliary space will be O(log N)

3. In Build Method for Binary Search in Java

Arrays.binarysearch() works for arrays which can be of primitive data type also.

Example: Binary Search program in Java using in-build method Arrays.binarysearch().

Java

// Java Program to demonstrate working of binarySearch()
// Method of Arrays class In a sorted array
import java.util.Arrays;

public class Geeks
{

    public static void main(String[] args)
    {
      	int a[] = { 10, 20, 15, 22, 35 };

        // Sorting the above array
        // using sort() method of Arrays class
        Arrays.sort(a);

        int x = 22;
        
      	int res = Arrays.binarySearch(a, x);
        
         System.out.println("Element to be searched is : "+ x);
         
        if (res >= 0)
            System.out.println(x + " found at index = " + res);
        else
            System.out.println(x + " Not found");

        x = 40;
        res = Arrays.binarySearch(a, x);
        
      	System.out.println("Element to be searched is : "+ x);
        if (res >= 0)
            System.out.println(x + " found at index = " + res);
        else
            System.out.println(x + " Not found");
    }
}

Output

Element to be searched is : 22
22 found at index = 3
Element to be searched is : 40
40 Not found