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Leap Year Program in C

Last Updated : 14 Jul, 2023
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A leap year is a year that contains an additional day in February month i.e. February 29. It means that a leap year has 366 days instead of the usual 365 days. In this article, we will see the program to check for leap year in C.

Conditions for a Leap Year

A leap year occurs once every four years and to check whether a year is a leap year, the following conditions should be satisfied:

  • It is a multiple of 4 but not of 100, or
  • It is a multiple of 400.

For example, 2000 is a leap year but 1900 is not.

Algorithm to Check Leap Year in C

IF year % 400 = 0
   PRINT "Leap Year"
ELSE IF year % 100 = 0
   PRINT "Not a Leap Year"
ELSE IF year % 4 = 0
   PRINT "Leap Year"
END IF
PRINT "Not a Leap Year"

Leap Year Program in C

C 
// C program to check if a given
// year is leap year or not
#include <stdbool.h>
#include <stdio.h>

bool checkYear(int year)
{
    // If a year is multiple of 400,
    // then it is a leap year
    if (year % 400 == 0)
        return true;

    // Else If a year is multiple of 100,
    // then it is not a leap year
    else if (year % 100 == 0)
        return false;

    // Else If a year is multiple of 4,
    // then it is a leap year
    else if (year % 4 == 0)
        return true;
    // if no above condition is satisfied, then it is not
    // a leap year
    return false;
}

// Driver code
int main()
{
    int year = 2000;

    if (checkYear(year)) {
        printf("Leap Year");
    }
    else {
        printf("Not a Leap Year");
    }
    return 0;
}

Output
Leap Year

Complexity Analysis

  • Time Complexity: O(1)
  • Auxiliary Space: O(1)

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Leap Year Program in C

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