基于BMP格式的隐写术

from PIL import Image import numpy as np import matplotlib.pyplot as plt import os,sys #字符串转化8位ASCII def InfoToStr(data): str='' for i in range(0,len(data)): a = ''.join([bin(ord(c)).replace('0b', '') for c in data[i]]) a = a.zfill(8)#向左添0，补全8位 str=str+a return list(str)#返回一个字符数组 #打开图片获取像素值，并加密 def EnImg(information): k=0 img = Image.open('1.bmp') width,height=img.size #获取图片的分辨率 if width * height * 3 - 8 < len(information): print("加密信息过长！") else: img_array = img.load(); #遍历图片每一个像素 for i in range(0, height): for j in range(0,width): r,g,b=img_array[j,i]#获取该位置的RGB值 R,k = BoolAndEncode(r, information, k) G,k = BoolAndEncode(g, information, k) B,k = BoolAndEncode(b, information, k) img_array[j,i]=(R,G,B) img.save('2.bmp') #判断是否超出加密字符长度和对像素最低位进行修改 def BoolAndEncode(img_rgb,data,i):#像素，加密字符串，当前加密信息字符的位置 img_rgb=dec2bin(img_rgb)#转为二进制 if(i<len(data)): if(data[i]==0):#将像素最低位变为0 img_rgb[7] = 0 else:#将像素最低位变为1 img_rgb[7] = 1 if(i>=len(data) ):#and i<len(data)+8 img_rgb[7] = 1 img_rgb = bin2dec(img_rgb)#转为十进制 i=i+1 return img_rgb,i #str数组转int数组 def StrToInt(info): info = [int(info) for info in info if info] return info #十进制to二进制  def dec2bin(num): mid=[] while num != 0 : rem = num%2 num = int(num/2) mid.insert(0,rem) for i in range(len(mid),8): mid.insert(0,0) return mid#返回一个二进制数组列表 #二进制to十进制 def bin2dec(num): s = '' for i in range(0, 8): s = s + str(num[i]) a = int(s, 2) return a#返回一个整数 #主函数 #information = input("输入加密信息：") information=open('数据.txt','rb').read().decode('gbk') information = InfoToStr(information) information = StrToInt(information) #print(information) EnImg(information)