Skip to main content

Get Support
Have a question? Let's get you an answer!

How Do I...? Troubleshooting Code & Webhooks Developer Zone

Other Help Resources
Wait, there's more! Check out these Community sourced spaces for additional resources.

Zapier Help Center Hire an Expert

Learning Resources
All of our best learning resources can be found here.

Featured Articles Show & Tell Zapier's products AI Hub Zapier Tools Hub

Share your knowledge
Give back to the Community by sharing your automation wins and helping to answer questions.

Share your success See unanswered questions User Groups

Other Learning Resources
Some of our favorite additional ways to upskill your Zapier knowledge.

Zapier Learn Zapier Blog Zapier Webinars

Product Updates
Check out what is new and upcoming with Zapier with our regular product updates.

Product Updates

Early Access Program
Want to join Early Access? Learn more here.

File Objects

Questions about working with file objects when building integrations on the Zapier platform.

  • 5 Topics
  • 7 Replies
5 Topics
M
Mazen RamadanNew
asked in File Objects
How to create an image file using its buffer

Hi,I do have a binary response of an image, i.e. “data:image/jpeg;base64,/9j/4AAQS ...”. In my app I convert this into a Buffer using `Buffer.from(response.content, 'binary');`. How do work with such binary data? My goal here is to save the binary into an image file. Any built-in actions to work with file system?Thanks

90
M
C
CMProdigyLinkNew
asked in File Objects
Files by Zapier showing only 10 rows

Hi everyone, I had a zap that utilized files by zapier. My csvs are all under 1mb and when I test my zap, I am only getting 10 rows returned. I need the entire file to be uploaded. Please advise.

281
Troy Tessalone
F
fsurracoNew
asked in File Objects
Enhancing Productboard Integration: Request for Additional Fields

Is there any plan to bring in more fields with the Productbaord integration? The zap i’ve created isn’t helpful given the limited data that is pulled in

221
Troy Tessalone
craibuc
craibucBeginner
asked in File Objects
Return a File object

I’m trying to return a file that can be used by other actions.This code converts the base-64 string that’s returned by an API into a File:const xml = require('pixl-xml');const perform = async (z, bundle) => { const xml = 'XML HERE' var body = xml.stringify( 'Document', xml ); const options = { url: 'https://www.domain.tld/get_file', method: 'POST', headers: { 'Content-Type': 'application/xml', }, body: body }; return z.request(options).then((response) => { response.throwForStatus(); response.data = xml.parse(response.content); if ( response.data.FILE ) { const buffer = Buffer.from(response.data.FILE`; const file = new File(buffer,'somefile.pdf', { type: 'application/octet-stream' }); return { file: file } } });};Unit and integration tests work as expected, but I get an error when I try to use this in a Zap:File is not defined What happened (You are seeing this because you are an admin): Starting POST request to http

5431
craibuc
A
ArmentBeginner
asked in File Objects
"File Object" output, need a how-to

I am researching for a way to export a file from our application into another app like Google Drive. However I’m running into some difficulty hydrating the file or making it a file object as described in https://help.zapier.com/hc/en-us/articles/8496259603341#file-fields-0-4. In my action step using the code below I’m taking a encoded file from our database and doing a base64 decode to get the file name, file type, the buffer stream, and buffer stream length.const encodedFile = bundle.inputData.file;const decodedFile = Buffer.from(encodedFile, 'base64').toString('utf-8'); var fileByte = Buffer.from(decodedFile.substring(decodedFile.indexOf('<File>')+6,decodedFile.indexOf('</File>')), 'base64').toString('utf-8'); var filetype =Buffer.from(decodedFile.substring(decodedFile.indexOf('<FileType>')+10,decodedFile.indexOf('</FileType>')), 'base64').toString('utf-8'); var filename = Buffer.from(decodedFile.substring(decodedFile.indexOf('<UploadedFileName>')

12224
A
Terms & Conditions