Write a Java program to count the characters in each word in a given sentence?

Examples:

Input : geeks for geeks
Output :
geeks->5
for->3
geeks->5

Approach:Here we have to find out number of words in a sentence and the corresponding character count of each word.

Here first we create an equivalent char array of given String.
Now we iterate the char array using for loop. Inside for loop we declare a String with empty implementation.
Whenever we found an alphabet we will perform concatenation of that alphabet with the String variable and increment the value of i.
Now when i reaches to a space it will come out from the while loop and now String variable has the word which is previous of space.
Now we will print the String variable with the length of the String.

Implementation:

JAVA

class CountCharacterInEachWords {
    static void count(String str)
    {
        // Create an char array of given String
        char[] ch = str.toCharArray();
        for (int i = 0; i < ch.length; i++) {

            // Declare an String with empty initialization
            String s = "";

            // When the character is not space
            while (i < ch.length && ch[i] != ' ') {

                // concat with the declared String
                s = s + ch[i];
                i++;
            }

            if (s.length() > 0) 
                System.out.println(s + "->" + s.length());            
        }
    }
    public static void main(String[] args)
    {
        String str = "geeks for geeks";
        count(str);
    }
}

Output

geeks->5
for->3
geeks->5

Time Complexity: O(|S|).
Auxiliary Space: O(|S|), where |S| is the length of the input string.

Approach: Using split( ) and temp array

Steps involved:

split the words based on spaces between the sentence.
Store the words in the temp array.
Now traverse the temp array and then by using length() find the length of each word.

Note : Sometimes split() function won't work properly when splitting should be done based on some regular expressions like

OR sign (|)
question mark (?)
asterisk (*)
plus sign (+)
backslash (\)
period (.)
caret (^)
square brackets ([ and ])
dollar sign ($)
ampersand (&)

We need to specify them as split("\\(split char)") where (split char) would be one of the character from the above regular expression.

Below is the implementation of the above approach.

Java

/*package whatever //do not write package name here */

import java.util.*;
class GFG {
    public static void main(String[] args) {
        
        String s="Geeks   For Geeks";
        count(s);
        
    }
    public static void count(String s)
    {
        //split method splitting the string
        // based on a space
        String[] temp=s.split("\\ ");
        
        for(String t: temp)
        {
            // checking whether the word is not empty
            if(t.length()>0)
            System.out.println(t+" -> "+t.length());
        }
    }
}
//This code is contributed by aeroabrar_31

Output

Geeks -> 5
For -> 3
Geeks -> 5

Time Complexity: O(|S|).
Auxiliary Space: O(|S|), where |S| is the length of the input string.

Java program to count the characters in each word in a given sentence

Approach: Using split( ) and temp array

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