C++ Program To Print Inverted Pyramid

An inverted pyramid pattern contains stars arranged in decreasing order of columns from the first row to the last.

• The number of elements decreases with each row.
• Nested loops are used to control spaces and symbols in the pattern.

Illustration

Input: n = 4

Inverted Half Pyramid Using *

* * * *

* * *

* *

*

Inverted Half Pyramid Using Numbers

1 2 3 4

1 2 3

1 2

1

Inverted Full Pyramid Using *

* * * * * * *

* * * * *

* * *

*

Inverted Half Pyramid Using *

For an inverted half pyramid, the first row contains n stars, and each subsequent row contains one fewer star. The outer loop controls the rows, while the inner loop prints the required number of stars.

using namespace std;
#include <bits/stdc++.h>
#include <iostream>
int main()
{
    int n = 4;
    for (int i = n; i >= 1; --i) {
        for (int j = 1; j <= i; ++j) {
            cout << "* ";
        }
        cout << endl;
    }

    return 0;
}

* * * * 
* * * 
* * 
* 

Inverted Half Pyramid Using Numbers

In this pattern, each row starts from 1 and prints numbers up to the current row length. The number of elements decreases from n to 1.

using namespace std;
#include <bits/stdc++.h>
#include <iostream>
int main()
{
    int n=4; // took a default value
    for (int i = n; i >= 1; --i) { // loop for iterating
        for (int j = 1; j <= i; ++j) { // loop for printing
            cout << j << " ";
        }
        cout << endl;
    }
    return 0;
}

1 2 3 4 
1 2 3 
1 2 
1 

Inverted Full Pyramid Using *

An inverted full pyramid is formed by printing spaces before the stars. For each row:

• The number of leading spaces increases.
• The number of stars decreases.
• The number of stars in each row is 2 * i - 1.

using namespace std;
#include <bits/stdc++.h>
#include <iostream>
int main()
{
    int n=5;
    for (int i = n; i >= 1; --i) {
        for (int k = 0; k < n - i; ++k) {
            cout << "  ";
        }
        for (int j = i; j <= 2 * i - 1; ++j) {
            cout << "* ";
        }
        for (int j = 0; j < i - 1; ++j) {
            cout << "* ";
        }
        cout << endl;
    }
    return 0;
}