C++ Program To Find If A Character Is Vowel Or Consonant

Last Updated : 12 Aug, 2026

In the English alphabet, the vowels are a, e, i, o, and u, while the remaining alphabetic characters are consonants. A character can be checked against these vowels to determine whether it is a vowel or consonant.

  • Both uppercase and lowercase vowels can be checked.
  • The character can be classified using conditional statements or a string search.

check vowel or cosonant character in c++

Approach 1: Using if-else Statement

The character is compared with each vowel using the logical OR (||) operator. If it matches any vowel, it is classified as a vowel; otherwise, it is classified as a consonant.

C++ 
#include <iostream>
using namespace std;

// Function to check whether a
// character is vowel or not
void vowelOrConsonant(char x)
{
    if (x == 'a' || x == 'e' || x == 'i' || x == 'o'
        || x == 'u' || x == 'A' || x == 'E' || x == 'I'
        || x == 'O' || x == 'U')
        cout << "Vowel" << endl;
    else
        cout << "Consonant" << endl;
}

// Driver code
int main()
{
    vowelOrConsonant('c');
    vowelOrConsonant('E');
    return 0;
}

Output
Consonant
Vowel

Approach 2: Using find()

The std::string::find() function can be used to search for the given character in a string containing all vowels. If the character is found, it is a vowel; otherwise, it is a consonant.

C++ 
#include <iostream>
#include <string>

using namespace std;

int isVowel(char ch)
{
    // Make the list of vowels
    string str = "aeiouAEIOU";
    return (str.find(ch) != string::npos);
}

// Driver code
int main()
{
    if (isVowel('a'))
        cout << "a is vowel" << endl;
    else
        cout << "a is consonant" << endl;

    return 0;
}

Output
a is vowel
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